A014258 -id:A014258 - cp's OEIS frontend

A350766 Reversed sum of the two previous terms, with a(1) = 1 and a(2) = 11.

1, 11, 21, 23, 44, 76, 21, 79, 1, 8, 9, 71, 8, 97, 501, 895, 6931, 6287, 81231, 81578, 908261, 938989, 527481, 746641, 2214721, 2631692, 3146484, 6718775, 9525689, 46444261, 5996955, 61214425, 8311276, 10752596, 27836091, 78688583

Offset: 1

Tim Ricchuiti, Jan 14 2022

Given two initial terms, sum the terms and reverse the digits of the sum. Then repeat.

Related to A014258, the Iccanobif numbers, but with initial terms 1 and 11 rather than 0 and 1.

Cf. A014258 but with initial terms 1 and 11 rather than 0 and 1.

Clear[ BiF ]; BiF[ 0 ]=1; BiF[ 1 ]=11; BiF[ n_Integer ] := BiF[ n ]=Plus@@(IntegerDigits[ BiF[ n-2 ]+BiF[ n-1 ], 10 ]//(#*Array[ 10^#&, Length[ # ], 0 ])&); Array[ BiF, 40, 0 ]
nxt[{a_, b_}]:={b, FromDigits[Reverse[IntegerDigits[a+b]]]}; Transpose[ NestList[ nxt, {0, 1}, 40]][[1]]

terms = [1, 11]
for i in range(100):
    terms.append(int(str(terms[-1]+terms[-2])[::-1]))
print(terms) # Gleb Ivanov, Jan 14 2022

cp's OEIS Frontend

A350766 Reversed sum of the two previous terms, with a(1) = 1 and a(2) = 11.

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