cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A100400 Triangle read by rows: T(n,k) is the number of nonroot nodes of outdegree k (0<=k<=n-1) in all non-crossing trees with n edges.

Original entry on oeis.org

1, 4, 2, 21, 12, 3, 120, 72, 24, 4, 715, 440, 165, 40, 5, 4368, 2730, 1092, 312, 60, 6, 27132, 17136, 7140, 2240, 525, 84, 7, 170544, 108528, 46512, 15504, 4080, 816, 112, 8, 1081575, 692208, 302841, 105336, 29925, 6840, 1197, 144, 9, 6906900, 4440150, 1973400, 708400, 212520, 53130, 10780, 1680, 180, 10
Offset: 1

Views

Author

Emeric Deutsch, Dec 30 2004

Keywords

Comments

Row n contains n terms. Row sums yield A004319. Column 0 yields A045721.

Examples

			T(2,1)=2 because in the non-crossing trees /_, _\ and /\ we have 2 nonroot nodes of outdegree 1.
Triangle begins:
1;
4,2;
21,12,3;
120,72,24,4;
		

Crossrefs

Programs

  • Maple
    for n from 1 to 10 do seq((k+1)*binomial(3*n-k-2,2*n-1),k=0..n-1) od; # yields sequence in triangular form

Formula

T(n, k) = (k+1)binomial(3n-k-2, 2n-1) (0<=k<=n-1).

A101372 Triangle read by rows: T(n,k) is number of leaves at level k in all noncrossing rooted trees on n+1 nodes.

Original entry on oeis.org

1, 2, 2, 7, 10, 4, 30, 50, 32, 8, 143, 260, 208, 88, 16, 728, 1400, 1280, 704, 224, 32, 3876, 7752, 7752, 5016, 2128, 544, 64, 21318, 43890, 46816, 33880, 17248, 5984, 1280, 128, 120175, 253000, 283360, 222640, 128800, 54400, 16000, 2944, 256
Offset: 1

Views

Author

Emeric Deutsch, Jan 14 2005

Keywords

Comments

Row n has n terms. Row sums yield A045721. Column 1 is A006013.

Examples

			Triangle begins:
1;
2,2;
7,10,4;
30,50,32,8;
143,260,208,88,16;
...
		

Crossrefs

Programs

  • Maple
    T:=(n,k)->2^(k-1)*(3*k-1)*binomial(3*n-2,n-k)/(2*n+k-1): for n from 1 to 10 do seq(T(n,k),k=1..n) od; # yields triangle in triangular form
  • Mathematica
    Flatten[Table[2^(k-1) ((3k-1)/(2n+k-1))Binomial[3n-2,n-k],{n,10},{k,n}]] (* Harvey P. Dale, Feb 10 2015 *)

Formula

T(n, k) = 2^(k-1)*[(3k-1)/(2n+k-1)]binomial(3n-2, n-k) (1<=k<=n).
G.f.: t*z*g^2/(1-2*t*z*g^3), where g = 1 + z*g^3 is the g.f. of the ternary numbers (A001764).
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