0, 1, 2, 3, 5, 4, 6, 8, 7, 12, 13, 11, 9, 10, 15, 14, 19, 21, 22, 16, 20, 17, 18, 31, 32, 34, 35, 36, 30, 33, 28, 23, 24, 29, 25, 26, 27, 40, 41, 39, 37, 38, 52, 51, 56, 58, 59, 60, 62, 63, 64, 43, 42, 53, 57, 61, 44, 54, 45, 46, 47, 55, 48, 49, 50, 87, 88, 90, 91, 92, 96, 97, 99
Offset: 0
To obtain this signature permutation, we apply these transformations to the binary trees as encoded and ordered by A014486 and for each n, a(n) will be the position of the tree to which the n-th tree transforms to, as follows:
...................one tree of one internal........2 trees of 2 internal nodes
..empty tree.........(non-leaf) node.................................
........................................................\/.......\/..
......x......................\/........................\/.........\/.
n=....0......................1..........................2..........3.
a(n)=.0......................1..........................2..........3.(all these trees are fixed by this transformation)
however, the next 5 trees, with 3 internal nodes, in range [A014137[2], A014138[2]] = [4,8] change as follows:
........\/.....\/.................\/.....\/...
.......\/.......\/.....\/.\/.....\/.......\/..
......\/.......\/.......\_/.......\/.......\/.
n=.....4........5........6........7........8..
....................|.........................
....................|.........................
....................V.........................
......\/.........\/.............\/.........\/.
.......\/.......\/.....\/.\/.....\/.......\/..
......\/.......\/.......\_/.......\/.......\/.
a(n)=..5........4........6........8........7..
thus we obtain the first nine terms of this sequence: 0,1,2,3,5,4,6,8,7,...
Comments