cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Previous Showing 11-13 of 13 results.

A244924 Odd integers n such that for every integer k>0, n*2^k-1 has a divisor in the set { 3, 5, 7, 13, 17, 97, 673 }.

Original entry on oeis.org

73520771, 108288041, 127499219, 141239113, 160792529, 198545797, 205293103, 217763051, 227258803, 262056089, 269931509, 303224819, 307060289, 353982553, 368427809, 430034677, 525141899, 581603107, 585721991, 600824113, 612314921, 644606467, 718519237, 723522461
Offset: 1

Views

Author

Pierre CAMI, Jul 08 2014

Keywords

Comments

For n > 96 a(n) = a(n-96) + 3029691210, the first 96 values are given in the table.

Crossrefs

Formula

For n > 96 a(n)=a(n-96) + 3029691210

A244351 Integers n such that for every integer k>0, n*6^k-1 has a divisor in the set { 7, 13, 31, 37, 97 }.

Original entry on oeis.org

84687, 429127, 508122, 1273238, 1570311, 1656045, 2574762, 2847748, 3048732, 3345805, 3849481, 5076399, 5324003, 5338292, 5908351, 6961919, 7639428, 8167823, 8508662, 8994775, 9078721, 9421866, 9936270, 9950261
Offset: 1

Views

Author

Pierre CAMI, Jun 26 2014

Keywords

Comments

For n > 24 a(n) = a(n-24) + 10124569, the first 24 values are in the data.
When the number a(n) has 1 or 6 as the last digit the number a(n)*6^k-1 is always divisible by 5 and have always a divisor in the set { 7, 13, 31, 37, 97 } for every k.

Crossrefs

Formula

For n>24 a(n) = a(n-24) + 10124569.

A244549 Integers m such that for every integer k>0, m*6^k+1 has a divisor in the set { 7, 13, 31, 37, 97 }.

Original entry on oeis.org

174308, 188299, 702703, 1045848, 1129794, 1615907, 1956746, 2485141, 3162650, 4216218, 4786277, 4800566, 5048170, 6275088, 6778764, 7075837, 7276821, 7549807, 8468524, 8554258, 8851331, 9616447, 9695442, 10039882
Offset: 1

Views

Author

Pierre CAMI, Jun 29 2014

Keywords

Comments

For n > 24 a(n) = a(n-24) + 10124569, the first 24 values are in the data.
When the number a(n) has 4 or 9 as the last digit the number a(n)*6^k-1 is always divisible by 5 and have always a divisor in the set { 7, 13, 31, 37, 97 } for every k.

Crossrefs

Formula

For n > 24 a(n) = a(n-24) + 10124569.
Previous Showing 11-13 of 13 results.