cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A265404 a(n) = number of Spironacci numbers (A078510) needed to sum to n using the greedy algorithm.

Original entry on oeis.org

0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 1, 2, 2, 1, 2, 2, 1, 2, 2, 1, 2, 2, 2, 1, 2, 2, 2, 2, 1, 2, 2, 2, 2, 2, 1, 2, 2, 2, 2, 2, 1, 2, 2, 2, 2, 2, 1, 2, 2, 2, 2, 2, 2, 1, 2, 2, 2, 2, 2, 2, 2, 1, 2, 2, 2, 2, 2, 2, 2, 2, 1, 2, 2, 2, 2, 2, 2, 2, 2, 2, 1, 2, 2, 2, 2, 2, 2, 2, 2, 2, 1, 2
Offset: 0

Views

Author

Antti Karttunen, Dec 16 2015

Keywords

Comments

a(0) = 0, because no numbers are needed to form an empty sum, which is zero.
First 2 occurs as a(17), first 3 at a(234), first 4 at a(3266).

Examples

			For n=17, the largest Spironacci number <= 17 is 16 (= A078510(22)). 17 - 16 = 1, which is A078510(1), thus 17 = A078510(22) + A078510(1), requiring only two such numbers for its sum, thus a(17) = 2.
For n=234, the largest Spironacci number <= 234 is 217 (= A078510(45)). 234-217 = 17 (whose decomposition is shown above), so 234 = A078510(45) + A078510(22) + A078510(1), thus a(234) = 3.
		

Crossrefs

Cf. A078510 (from its term a(7) onward gives also the positions of ones here).

A364381 Starts of runs of 3 consecutive integers that are greedy Jacobsthal-Niven numbers (A364379).

Original entry on oeis.org

1, 2, 3, 4, 8, 9, 10, 14, 20, 26, 42, 43, 44, 84, 85, 86, 104, 115, 170, 182, 304, 344, 362, 414, 544, 682, 686, 692, 784, 854, 1014, 1370, 1384, 1504, 1673, 1685, 1706, 2224, 2315, 2358, 2730, 2731, 2732, 2763, 2774, 3243, 3594, 3702, 4144, 4688, 4864, 5046, 5408
Offset: 1

Views

Author

Amiram Eldar, Jul 21 2023

Keywords

Crossrefs

Programs

  • Mathematica
    consecGreedyJN[5500, 3] (* using the function consecGreedyJN from A364380 *)
  • PARI
    lista(5500, 3) \\ using the function lista from A364380

A364382 Starts of runs of 4 consecutive integers that are greedy Jacobsthal-Niven numbers (A364379).

Original entry on oeis.org

1, 2, 3, 8, 9, 42, 43, 84, 85, 2730, 2731, 5460, 5461, 21864, 21865, 59477, 60073, 66303, 75048, 112509, 156607, 174762, 174763, 283327, 312190, 320768, 349524, 349525, 351570, 354429, 374589, 384039, 479037, 504510, 527103, 624040, 625470, 656829, 688830, 711423
Offset: 1

Views

Author

Amiram Eldar, Jul 21 2023

Keywords

Crossrefs

Subsequence of A364379, A364380 and A364381.
A364383 is a subsequence.

Programs

  • Mathematica
    consecGreedyJN[72000, 4] (* using the function consecGreedyJN from A364380 *)
  • PARI
    lista(10^5, 4) \\ using the function lista from A364380

A265743 a(n) = number of terms of A005187 needed to sum to n using the greedy algorithm.

Original entry on oeis.org

0, 1, 2, 1, 1, 2, 3, 1, 1, 2, 1, 1, 2, 3, 2, 1, 1, 2, 1, 1, 2, 3, 1, 1, 2, 1, 1, 2, 3, 2, 2, 1, 1, 2, 1, 1, 2, 3, 1, 1, 2, 1, 1, 2, 3, 2, 1, 1, 2, 1, 1, 2, 3, 1, 1, 2, 1, 1, 2, 3, 2, 2, 3, 1, 1, 2, 1, 1, 2, 3, 1, 1, 2, 1, 1, 2, 3, 2, 1, 1, 2, 1, 1, 2, 3, 1, 1, 2, 1, 1, 2, 3, 2, 2, 1, 1, 2, 1, 1, 2, 3, 1, 1, 2, 1, 1, 2, 3, 2, 1, 1, 2, 1, 1, 2, 3, 1, 1, 2, 1, 1, 2, 3, 2, 2, 3, 4, 1, 1
Offset: 0

Views

Author

Antti Karttunen, Dec 17 2015

Keywords

Comments

a(0) = 0, because no numbers are needed to form an empty sum, which is zero.

Crossrefs

Formula

Other identities. For all n >= 1:
a(A005187(n)) = 1 and a(A055938(n)) > 1.

A265746 Jacobsthal greedy base (A265747) interpreted as base-3 numbers, then shown in decimal.

Original entry on oeis.org

0, 1, 2, 3, 4, 9, 10, 11, 12, 13, 18, 27, 28, 29, 30, 31, 36, 37, 38, 39, 40, 81, 82, 83, 84, 85, 90, 91, 92, 93, 94, 99, 108, 109, 110, 111, 112, 117, 118, 119, 120, 121, 162, 243, 244, 245, 246, 247, 252, 253, 254, 255, 256, 261, 270, 271, 272, 273
Offset: 0

Views

Author

Antti Karttunen, Dec 17 2015

Keywords

Comments

Analogously to "Fibbinary numbers" (A003714) and "Catquaternary numbers" (A244161), this sequence could be called "Jacoternary numbers".

Crossrefs

Programs

Formula

a(0) = 0; for n >= 1, a(n) = 3^(A130249(n)-2) + a(n - A001045(A130249(n))).

A372556 a(n) = largest number k <= A130249(n) for which A372555(n-A001045(k)) = A372555(n)-1, where A372555(n) is the least number of Jacobsthal numbers that add up to n.

Original entry on oeis.org

0, 2, 2, 3, 3, 4, 4, 4, 4, 4, 4, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 6, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 6, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8
Offset: 0

Views

Author

Antti Karttunen, May 07 2024

Keywords

Comments

An auxiliary sequence for computing A372555 with a mutually recursive algorithm.
Differs from A130249 for the first time at n=63, 84, 191, 212, 255, etc. See A372558.
Conjecture: For all n, either a(n) = A130249(n) or a(n) = A130249(n)-1. In other words, there is always a minimal solution (in number of summands) for representing n as a sum of Jacobsthal numbers that its largest summand is either A001045(A130249(n)) [same as obtained with a greedy algorithm A265745], or the next smaller Jacobsthal number. - Antti Karttunen, May 10 2024

Crossrefs

Programs

  • PARI
    up_to = 87381; \\ = A001045(18).
    A001045(n) = (2^n - (-1)^n) / 3;
    A130249(n) = (#binary(3*n+1)-1);
    A372555_or_556list(up_to_n,return_556_instead) = { my(v372555 = vector(up_to_n), v372556 = vector(up_to_n)); v372555[1] = 1; v372556[1] = 2; for(n=2,#v372556, my(m=-1,mk=-1,s=A130249(n)); if(A001045(s)==n, v372555[n] = 1; v372556[n] = s, forstep(k=s, 1, -1, my(c=v372555[n-A001045(k)]); if(m<0 || cA001045(mk)])); if(return_556_instead,v372556,v372555); };
    v372556 = A372555_or_556list(up_to,1);
    A372556(n) = if(!n,n,v372556[n]);
    
  • Scheme
    ;; Use the program given in A372555.
Previous Showing 11-16 of 16 results.