cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Previous Showing 11-20 of 43 results. Next

A296848 Decimal expansion of limiting power-ratio for A295953; see Comments.

Original entry on oeis.org

7, 1, 9, 6, 6, 0, 1, 3, 6, 5, 3, 8, 3, 9, 1, 2, 4, 1, 2, 3, 9, 2, 7, 5, 8, 1, 7, 9, 2, 5, 3, 4, 9, 7, 9, 1, 3, 4, 3, 3, 3, 3, 3, 2, 6, 8, 1, 1, 3, 1, 1, 0, 4, 1, 1, 9, 0, 0, 0, 0, 8, 9, 5, 7, 3, 1, 1, 9, 7, 7, 7, 1, 1, 8, 2, 7, 6, 4, 6, 5, 9, 8, 7, 7, 7, 7
Offset: 1

Views

Author

Clark Kimberling, Jan 06 2018

Keywords

Comments

Suppose that A = (a(n)), for n >= 0, is a sequence, and g is a real number such that a(n)/a(n-1) -> g. The limiting power-ratio for A is the limit as n->oo of a(n)/g^n, assuming that this limit exists. For A = A295953, we have g = (1 + sqrt(5))/2, the golden ratio (A001622). See the guide at A296469 for related sequences.

Examples

			limiting power-ratio = 7.090700687355142881167747526503371215921...
		

Crossrefs

Programs

  • Mathematica
    a[0] = 1; a[1] = 3; b[0] = 2; b[1 ] = 4; b[2] = 5;
    a[n_] := a[n] = a[n - 1] + a[n - 2] + b[n] + 1;
    j = 1; While[j < 13, k = a[j] - j - 1;
    While[k < a[j + 1] - j + 1, b[k] = j + k + 2; k++]; j++];
    Table[a[n], {n, 0, k}]; (* A295953 *)
    z = 2000; g = GoldenRatio; h = Table[N[a[n]/g^n, z], {n, 0, z}];
    StringJoin[StringTake[ToString[h[[z]]], 41], "..."]
    Take[RealDigits[Last[h], 10][[1]], 120]   (* A296848 *)

A296471 Decimal expansion of ratio-sum for A295947; see Comments.

Original entry on oeis.org

2, 4, 2, 7, 1, 7, 9, 4, 8, 8, 0, 5, 6, 0, 3, 9, 4, 2, 4, 4, 2, 3, 6, 5, 3, 1, 0, 3, 8, 3, 1, 4, 5, 2, 2, 5, 1, 7, 5, 7, 9, 1, 6, 7, 4, 0, 4, 7, 2, 5, 2, 8, 1, 6, 7, 7, 2, 3, 6, 8, 5, 3, 1, 6, 1, 6, 1, 1, 0, 1, 7, 9, 1, 4, 9, 8, 4, 2, 4, 8, 6, 3, 8, 9, 7, 1
Offset: 1

Views

Author

Clark Kimberling, Dec 18 2017

Keywords

Comments

Suppose that A = (a(n)), for n >= 0, is a sequence, and g is a real number such that a(n)/a(n-1) -> g. The ratio-sum for A is |a(1)/a(0) - g| + |a(2)/a(1) - g| + ..., assuming that this series converges. For A = A295947, we have g = (1 + sqrt(5))/2, the golden ratio (A001622). See the guide at A296469 for related sequences.

Examples

			ratio-sum = 2.427179488056039424423653103831452251757...
		

Crossrefs

Programs

  • Mathematica
    a[0] = 2; a[1] = 4; b[0] = 1; b[1 ] = 3; b[2] = 5;
    a[n_] := a[n] = a[n - 1] + a[n - 2] + b[n];
    j = 1; While[j < 13, k = a[j] - j - 1;
    While[k < a[j + 1] - j + 1, b[k] = j + k + 2; k++]; j++];
    Table[a[n], {n, 0, k}]; (* A295947 *)
    g = GoldenRatio; s = N[Sum[- g + a[n]/a[n - 1], {n, 1, 1000}], 200]
    Take[RealDigits[s, 10][[1]], 100]  (* A296471 *)

A296472 Decimal expansion of limiting power-ratio for A295947; see Comments.

Original entry on oeis.org

7, 1, 7, 1, 3, 5, 1, 0, 4, 5, 0, 4, 1, 1, 3, 7, 7, 9, 7, 3, 9, 8, 2, 0, 5, 6, 7, 8, 3, 8, 8, 6, 9, 0, 1, 2, 5, 2, 7, 3, 0, 9, 1, 9, 4, 5, 7, 5, 2, 5, 4, 8, 1, 3, 3, 8, 9, 9, 1, 3, 2, 6, 5, 4, 9, 3, 0, 1, 8, 9, 2, 6, 1, 7, 4, 8, 7, 3, 2, 3, 0, 2, 9, 2, 8, 4
Offset: 1

Views

Author

Clark Kimberling, Dec 18 2017

Keywords

Comments

Suppose that A = (a(n)), for n >=0, is a sequence, and g is a real number such that a(n)/a(n-1) -> g. The limiting power-ratio for A is the limit as n->oo of a(n)/g^n, assuming that this limit exists. For A = A295947 we have g = (1 + sqrt(5))/2, the golden ratio (A001622). See the guide at A296469 for related sequences.

Examples

			limiting power-ratio = 7.171351045041137797398205678388690125273...
		

Crossrefs

Programs

  • Mathematica
    a[0] = 2; a[1] = 4; b[0] = 1; b[1 ] = 3; b[2] = 5;
    a[n_] := a[n] = a[n - 1] + a[n - 2] + b[n];
    j = 1; While[j < 12, k = a[j] - j - 1;
     While[k < a[j + 1] - j + 1, b[k] = j + k + 2; k++]; j++];
    Table[a[n], {n, 0, 15}]  (* A295947 *)
    z = 2000; g = GoldenRatio; h = Table[N[a[n]/g^n, z], {n, 0, z}];
    StringJoin[StringTake[ToString[h[[z]]], 41], "..."]
    Take[RealDigits[Last[h], 10][[1]], 120] (* A296472 *)

A296473 Decimal expansion of ratio-sum for A295948; see Comments.

Original entry on oeis.org

1, 9, 1, 6, 9, 7, 8, 1, 0, 6, 7, 4, 3, 3, 0, 0, 9, 2, 8, 4, 3, 4, 3, 2, 3, 0, 5, 8, 9, 7, 4, 4, 1, 8, 6, 0, 8, 1, 2, 1, 0, 1, 4, 8, 6, 7, 3, 4, 8, 9, 3, 4, 8, 1, 6, 8, 6, 2, 1, 7, 8, 6, 1, 9, 0, 5, 3, 1, 1, 3, 9, 4, 9, 7, 7, 9, 9, 8, 6, 6, 6, 0, 6, 0, 4, 0
Offset: 1

Views

Author

Clark Kimberling, Dec 19 2017

Keywords

Comments

Suppose that A = (a(n)), for n >= 0, is a sequence, and g is a real number such that a(n)/a(n-1) -> g. The ratio-sum for A is |a(1)/a(0) - g| + |a(2)/a(1) - g| + ..., assuming that this series converges. For A = A295948, we have g = (1 + sqrt(5))/2, the golden ratio (A001622). See the guide at A296469 for related sequences.

Examples

			ratio-sum = 1.916978106743300928434323058974418608121...
		

Crossrefs

Programs

  • Mathematica
    a[0] = 3; a[1] = 4; b[0] = 1; b[1 ] = 2; b[2] = 5;
    a[n_] := a[n] = a[n - 1] + a[n - 2] + b[n];
    j = 1; While[j < 13, k = a[j] - j - 1;
    While[k < a[j + 1] - j + 1, b[k] = j + k + 2; k++]; j++];
    Table[a[n], {n, 0, k}]; (* A295948 *)
    g = GoldenRatio; s = N[Sum[- g + a[n]/a[n - 1], {n, 1, 1000}], 200]
    Take[RealDigits[s, 10][[1]], 100]  (* A296473 *)

A296474 Decimal expansion of limiting power-ratio for A295948; see Comments.

Original entry on oeis.org

7, 4, 3, 2, 1, 3, 8, 6, 5, 6, 0, 2, 2, 4, 6, 4, 6, 9, 8, 6, 0, 3, 7, 4, 4, 7, 6, 2, 9, 9, 9, 1, 5, 0, 0, 0, 7, 5, 5, 1, 2, 5, 5, 0, 7, 1, 9, 6, 0, 8, 2, 8, 5, 9, 9, 8, 0, 3, 1, 0, 5, 5, 1, 5, 0, 6, 3, 4, 8, 4, 1, 8, 0, 3, 4, 0, 8, 6, 9, 6, 6, 3, 4, 8, 6, 3
Offset: 1

Views

Author

Clark Kimberling, Dec 19 2017

Keywords

Comments

Suppose that A = (a(n)), for n >= 0, is a sequence, and g is a real number such that a(n)/a(n-1) -> g. The limiting power-ratio for A is the limit as n->oo of a(n)/g^n, assuming that this limit exists. For A = A296948 we have g = (1 + sqrt(5))/2, the golden ratio (A001622). See the guide at A296469 for related sequences.

Examples

			limiting power-ratio = 7.432138656022464698603744762999150007551...
		

Crossrefs

Programs

  • Mathematica
    a[0] = 3; a[1] = 4; b[0] = 1; b[1 ] = 2; b[2] = 5;
    a[n_] := a[n] = a[n - 1] + a[n - 2] + b[n];
    j = 1; While[j < 12, k = a[j] - j - 1;
     While[k < a[j + 1] - j + 1, b[k] = j + k + 2; k++]; j++];
    Table[a[n], {n, 0, 15}]  (* A295948 *)
    z = 2000; g = GoldenRatio; h = Table[N[a[n]/g^n, z], {n, 0, z}];
    StringJoin[StringTake[ToString[h[[z]]], 41], "..."]
    Take[RealDigits[Last[h], 10][[1]], 120] (* A296474 *)

A296475 Decimal expansion of ratio-sum for A295949; see Comments.

Original entry on oeis.org

3, 9, 7, 5, 7, 8, 9, 5, 5, 7, 9, 7, 1, 0, 7, 3, 4, 7, 3, 4, 5, 4, 9, 6, 5, 3, 2, 6, 8, 4, 2, 9, 1, 7, 0, 7, 3, 1, 4, 4, 1, 2, 4, 7, 5, 0, 0, 4, 2, 6, 5, 2, 1, 5, 9, 1, 9, 2, 3, 7, 4, 8, 6, 6, 6, 7, 0, 5, 9, 2, 3, 2, 0, 2, 3, 6, 5, 0, 2, 4, 1, 3, 6, 7, 6, 3
Offset: 1

Views

Author

Clark Kimberling, Dec 19 2017

Keywords

Comments

Suppose that A = (a(n)), for n >= 0, is a sequence, and g is a real number such that a(n)/a(n-1) -> g. The ratio-sum for A is |a(1)/a(0) - g| + |a(2)/a(1) - g| + ..., assuming that this series converges. For A = A295949, we have g = (1 + sqrt(5))/2, the golden ratio (A001622). See the guide at A296469 for related sequences.

Examples

			ratio-sum = 3.975789557971073473454965326842917073144...
		

Crossrefs

Programs

  • Mathematica
    a[0] = 1; a[1] = 2; b[0] = 3; b[1 ] = 4; b[2] = 5;
    a[n_] := a[n] = a[n - 1] + a[n - 2] + b[n];
    j = 1; While[j < 13, k = a[j] - j - 1;
    While[k < a[j + 1] - j + 1, b[k] = j + k + 2; k++]; j++];
    Table[a[n], {n, 0, k}]; (* A295949 *)
    g = GoldenRatio; s = N[Sum[- g + a[n]/a[n - 1], {n, 1, 1000}], 200]
    Take[RealDigits[s, 10][[1]], 100]  (* A296475 *)

A296476 Decimal expansion of limiting power-ratio for A295949; see Comments.

Original entry on oeis.org

6, 1, 3, 6, 3, 8, 5, 5, 1, 8, 6, 6, 6, 2, 2, 0, 7, 9, 0, 9, 5, 5, 3, 4, 3, 9, 4, 9, 1, 5, 2, 6, 3, 6, 1, 2, 4, 4, 6, 0, 1, 1, 9, 2, 3, 6, 9, 8, 1, 2, 8, 5, 1, 9, 0, 7, 9, 6, 7, 5, 7, 1, 7, 2, 0, 2, 5, 9, 9, 5, 3, 7, 2, 2, 4, 5, 5, 6, 5, 5, 6, 2, 6, 0, 6, 6
Offset: 1

Views

Author

Clark Kimberling, Dec 19 2017

Keywords

Comments

Suppose that A = (a(n)), for n >= 0, is a sequence, and g is a real number such that a(n)/a(n-1) -> g. The limiting power-ratio for A is the limit as n->oo of a(n)/g^n, assuming that this limit exists. For A = A295949, we have g = (1 + sqrt(5))/2, the golden ratio (A001622). See the guide at A296469 for related sequences.

Examples

			limiting power-ratio = 6.136385518666220790955343949152636124460...
		

Crossrefs

Programs

  • Mathematica
    a[0] = 1; a[1] = 2; b[0] = 3; b[1 ] = 4; b[2] = 5;
    a[n_] := a[n] = a[n - 1] + a[n - 2] + b[n];
    j = 1; While[j < 13, k = a[j] - j - 1;
     While[k < a[j + 1] - j + 1, b[k] = j + k + 2; k++]; j++];
    Table[a[n], {n, 0, k}]; (* A295949 *)
    z = 2000; g = GoldenRatio; h = Table[N[a[n]/g^n, z], {n, 0, z}];
    StringJoin[StringTake[ToString[h[[z]]], 41], "..."]
    Take[RealDigits[Last[h], 10][[1]], 120]   (* A296476 *)

Extensions

Definition and sequence corrected by Clark Kimberling, Jan 05 2018

A296477 Decimal expansion of ratio-sum for A295950; see Comments.

Original entry on oeis.org

4, 2, 8, 9, 9, 6, 9, 2, 7, 3, 6, 3, 8, 3, 1, 8, 1, 9, 5, 4, 8, 3, 3, 7, 9, 9, 6, 0, 2, 5, 5, 5, 3, 4, 9, 1, 7, 7, 5, 3, 3, 7, 3, 8, 4, 0, 6, 3, 1, 3, 9, 4, 4, 0, 3, 3, 8, 1, 3, 6, 5, 3, 4, 1, 0, 3, 3, 8, 5, 4, 0, 8, 0, 0, 4, 2, 2, 2, 2, 9, 7, 0, 9, 7, 2, 5
Offset: 1

Views

Author

Clark Kimberling, Jan 05 2018

Keywords

Comments

Suppose that A = (a(n)), for n >= 0, is a sequence, and g is a real number such that a(n)/a(n-1) -> g. The ratio-sum for A is |a(1)/a(0) - g| + |a(2)/a(1) - g| + ..., assuming that this series converges. For A = A295950, we have g = (1 + sqrt(5))/2, the golden ratio (A001622). See the guide at A296469 for related sequences.

Examples

			ratio-sum = 4.289969273638318195483379960255534917753...
		

Crossrefs

Programs

  • Mathematica
    a[0] = 1; a[1] = 4; b[0] = 2; b[1 ] = 3; b[2] = 5;
    a[n_] := a[n] = a[n - 1] + a[n - 2] + b[n];
    j = 1; While[j < 13, k = a[j] - j - 1;
    While[k < a[j + 1] - j + 1, b[k] = j + k + 2; k++]; j++];
    Table[a[n], {n, 0, k}]; (* A295950 *)
    g = GoldenRatio; s = N[Sum[- g + a[n]/a[n - 1], {n, 1, 1000}], 200]
    Take[RealDigits[s, 10][[1]], 100]  (* A296477 *)

A296478 Decimal expansion of limiting power-ratio for A295950; see Comments.

Original entry on oeis.org

6, 9, 2, 0, 2, 0, 8, 3, 1, 1, 6, 9, 3, 1, 5, 9, 1, 0, 8, 5, 8, 8, 2, 1, 3, 4, 0, 8, 4, 9, 4, 1, 9, 8, 7, 0, 5, 7, 3, 8, 6, 7, 8, 6, 9, 1, 5, 5, 2, 6, 8, 4, 6, 2, 5, 3, 7, 6, 6, 9, 9, 3, 8, 5, 4, 7, 1, 8, 2, 0, 5, 8, 1, 2, 0, 8, 6, 0, 7, 4, 0, 3, 5, 6, 5, 8
Offset: 1

Views

Author

Clark Kimberling, Jan 05 2018

Keywords

Comments

Suppose that A = (a(n)), for n >= 0, is a sequence, and g is a real number such that a(n)/a(n-1) -> g. The limiting power-ratio for A is the limit as n->oo of a(n)/g^n, assuming that this limit exists. For A = A295950, we have g = (1 + sqrt(5))/2, the golden ratio (A001622). See the guide at A296469 for related sequences.

Examples

			limiting power-ratio = 6.920208311693159108588213408494198705738...
		

Crossrefs

Programs

  • Mathematica
    a[0] = 1; a[1] = 4; b[0] = 2; b[1 ] = 3; b[2] = 5;
    a[n_] := a[n] = a[n - 1] + a[n - 2] + b[n];
    j = 1; While[j < 13, k = a[j] - j - 1;
     While[k < a[j + 1] - j + 1, b[k] = j + k + 2; k++]; j++];
    Table[a[n], {n, 0, k}]; (* A295950 *)
    z = 2000; g = GoldenRatio; h = Table[N[a[n]/g^n, z], {n, 0, z}];
    StringJoin[StringTake[ToString[h[[z]]], 41], "..."]
    Take[RealDigits[Last[h], 10][[1]], 120]   (* A296478 *)

A296479 Decimal expansion of ratio-sum for A295951; see Comments.

Original entry on oeis.org

2, 5, 7, 1, 9, 7, 1, 3, 6, 9, 3, 0, 7, 5, 7, 8, 2, 4, 5, 3, 4, 0, 6, 7, 2, 4, 8, 9, 6, 7, 2, 0, 8, 7, 6, 5, 9, 8, 7, 6, 8, 8, 8, 2, 5, 4, 5, 3, 3, 3, 9, 6, 3, 8, 1, 9, 6, 8, 6, 9, 0, 7, 4, 2, 8, 4, 3, 0, 5, 5, 0, 2, 3, 7, 4, 6, 4, 3, 3, 1, 8, 4, 7, 3, 5, 0
Offset: 1

Views

Author

Clark Kimberling, Jan 05 2018

Keywords

Comments

Suppose that A = (a(n)), for n >= 0, is a sequence, and g is a real number such that a(n)/a(n-1) -> g. The ratio-sum for A is |a(1)/a(0) - g| + |a(2)/a(1) - g| + ..., assuming that this series converges. For A = A295951, we have g = (1 + sqrt(5))/2, the golden ratio (A001622). See the guide at A296469 for related sequences.

Examples

			ratio-sum = 2.571971369307578245340672489672087659876...
		

Crossrefs

Programs

  • Mathematica
    a[0] = 2; a[1] = 3; b[0] = 1; b[1 ] = 4; b[2] = 5;
    a[n_] := a[n] = a[n - 1] + a[n - 2] + b[n];
    j = 1; While[j < 13, k = a[j] - j - 1;
    While[k < a[j + 1] - j + 1, b[k] = j + k + 2; k++]; j++];
    Table[a[n], {n, 0, k}]; (* A295951 *)
    g = GoldenRatio; s = N[Sum[- g + a[n]/a[n - 1], {n, 1, 1000}], 200]
    Take[RealDigits[s, 10][[1]], 100]  (* A296479 *)
Previous Showing 11-20 of 43 results. Next