cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A318234 Number of inequivalent leaf-colorings of totally transitive rooted trees with n nodes.

Original entry on oeis.org

1, 1, 2, 5, 13, 34, 87
Offset: 1

Views

Author

Gus Wiseman, Aug 21 2018

Keywords

Comments

A rooted tree is totally transitive if every branch of the root is totally transitive and every branch of a branch of the root is also a branch of the root.

Examples

			Inequivalent representatives of the a(6) = 34 leaf-colorings:
  (11(11))  (11111)  (111(1))  (1(111))  (1(1)(1))
  (11(12))  (11112)  (111(2))  (1(112))  (1(1)(2))
  (11(22))  (11122)  (112(1))  (1(122))  (1(2)(2))
  (11(23))  (11123)  (112(2))  (1(123))  (1(2)(3))
  (12(11))  (11223)  (112(3))  (1(222))
  (12(12))  (11234)  (123(1))  (1(223))
  (12(13))  (12345)  (123(4))  (1(234))
  (12(33))
  (12(34))
		

Crossrefs

A339648 Number of series reduced trees with n nodes and integer labeled leaves covering an initial interval of positive integers.

Original entry on oeis.org

1, 0, 2, 4, 16, 62, 290, 1496, 8548, 53278, 359076, 2597052, 20034252, 163996372, 1418326160, 12911494594, 123317867572, 1232219079760, 12848961783474, 139505358593240, 1573914932077692, 18418287165450500, 223191801317514104, 2796501582165674166, 36179439053130339742
Offset: 1

Views

Author

Andrew Howroyd, Dec 11 2020

Keywords

Comments

Only leaves are labeled.

Examples

			a(4) = 4: (111), (112), (122), (123).
a(5) = 16: (1111), (1112), (1122), (1123), (1222), (1223), (1233), (1234), (1(11)), (1(12)), (1(22)), (1(23)), (2(11)), (2(12)), (2(13)), (3(12)).
		

Crossrefs

Cf. A001678 (uncolored), A318231 (inequivalent colorings).

Programs

  • PARI
    \\ here R(n,k) gives number of colorings with k colors as vector.
    EulerT(v)={Vec(exp(x*Ser(dirmul(v,vector(#v,n,1/n))))-1, -#v)}
    R(n,k)={my(v=vector(n)); v[1]=k; for(n=2, #v, v[n] = EulerT(concat(v[1..n-2], [0]))[n-1]); v}
    seq(n)={sum(k=1, n, R(n, k)*sum(r=k, n, binomial(r, k)*(-1)^(r-k)))}
Previous Showing 11-12 of 12 results.