cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Previous Showing 11-19 of 19 results.

A352511 Starts of runs of 4 consecutive Catalan-Niven numbers (A352508).

Original entry on oeis.org

144, 15630, 164862, 202761, 373788, 450189, 753183, 1403961, 1779105, 2588415, 2673774, 2814229, 2850880, 3009174, 3013722, 3045870, 3091023, 3702390, 3942519, 4042950, 4432128, 4725432, 4938348, 5718942, 5907312, 6268248, 6519615, 6592752, 6791379, 7095492, 8567802
Offset: 1

Views

Author

Amiram Eldar, Mar 19 2022

Keywords

Comments

Conjecture: There are no runs of 5 consecutive Catalan-Niven numbers (checked up to 10^9).

Examples

			144 is a term since 144, 145, 146 and 147 are all divisible by the sum of the digits in their Catalan representation:
    k  A014418(k)  A014420(k)  k/A014420(k)
  ---  ----------  ----------  ------------
  144      100210           4            36
  145      100211           5            29
  146      101000           2            73
  147      101001           3            49
		

Crossrefs

Programs

  • Mathematica
    c[n_] := c[n] = CatalanNumber[n]; catNivQ[n_] := Module[{s = {}, m = n, i}, While[m > 0, i = 1; While[c[i] <= m, i++]; i--; m -= c[i]; AppendTo[s, i]]; Divisible[n, Plus @@ IntegerDigits[Total[4^(s - 1)], 4]]]; seq[count_, nConsec_] := Module[{cn = catNivQ /@ Range[nConsec], s = {}, c = 0, k = nConsec + 1}, While[c < count, If[And @@ cn, c++; AppendTo[s, k - nConsec]]; cn = Join[Rest[cn], {catNivQ[k]}]; k++]; s]; seq[5, 4]

A364219 Starts of runs of 4 consecutive integers that are Jacobsthal-Niven numbers (A364216).

Original entry on oeis.org

1, 42, 43, 2731, 11605, 13024, 14229, 25983, 39390, 45727, 46624, 47529, 60073, 96039, 111390, 131103, 132010, 133984, 134430, 140767, 148180, 148181, 148509, 174762, 174763, 187744, 197790, 237609, 247114, 266453, 275229, 287988, 312190, 330847, 354429, 370269
Offset: 1

Views

Author

Amiram Eldar, Jul 14 2023

Keywords

Crossrefs

Subsequence of A364216, A364217 and A364218.
Subsequences: A364220, A364221.

Programs

  • Mathematica
    consecJacobsthalNiven[4*10^5, 4] (* using the function from A364217 *)
  • PARI
    lista(4*10^5, 4) \\ using the function from A364217

A364382 Starts of runs of 4 consecutive integers that are greedy Jacobsthal-Niven numbers (A364379).

Original entry on oeis.org

1, 2, 3, 8, 9, 42, 43, 84, 85, 2730, 2731, 5460, 5461, 21864, 21865, 59477, 60073, 66303, 75048, 112509, 156607, 174762, 174763, 283327, 312190, 320768, 349524, 349525, 351570, 354429, 374589, 384039, 479037, 504510, 527103, 624040, 625470, 656829, 688830, 711423
Offset: 1

Views

Author

Amiram Eldar, Jul 21 2023

Keywords

Crossrefs

Subsequence of A364379, A364380 and A364381.
A364383 is a subsequence.

Programs

  • Mathematica
    consecGreedyJN[72000, 4] (* using the function consecGreedyJN from A364380 *)
  • PARI
    lista(10^5, 4) \\ using the function lista from A364380

A381584 Starts of runs of 4 consecutive integers that are all terms in A381581.

Original entry on oeis.org

1, 55, 2104, 5222, 24784, 63510, 64264, 69487, 95463, 121393, 184327, 327303, 374589, 463110, 468168, 561069, 572550, 596868, 671407, 740310, 759030, 819948, 902670, 956680, 1023009, 1036230, 1065030, 1259817, 1274910, 1359552, 1683154, 1714470, 1731750, 2182023
Offset: 1

Views

Author

Amiram Eldar, Feb 28 2025

Keywords

Comments

If k is congruent to 1 or 5 mod 12 (A087445), then A001906(k) = Fibonacci(2*k) is a term.

Examples

			1 is a term since A291711(1) = 1 divides 1, A291711(2) = 2 divides 2, A291711(3) = 1 divides 3, and A291711(4) = 2 divides 4.
55 is a term since A291711(55) = 1 divides 55, A291711(56) = 2 divides 56, A291711(57) = 3 divides 57, and A291711(58) = 2 divides 58.
		

Crossrefs

Subsequence of A381581, A381582 and A381583.
A381585 is a subsequence.
Similar sequences: A141769, A328211, A328215, A330933.

Programs

  • Mathematica
    f[n_] := f[n] = Fibonacci[2*n]; q[n_] := q[n] = Module[{s = 0, m = n, k}, While[m > 0, k = 1; While[m > f[k], k++]; If[m < f[k], k--]; If[m >= 2*f[k], s += 2; m -= 2*f[k], s++; m -= f[k]]]; Divisible[n, s]]; seq[count_, nConsec_] := Module[{cn = q /@ Range[nConsec], s = {}, c = 0, k = nConsec + 1}, While[c < count, If[And @@ cn, c++; AppendTo[s, k - nConsec]]; cn = Join[Rest[cn], {q[k]}]; k++]; s]; seq[12, 4]
  • PARI
    mx = 20; fvec = vector(mx, i, fibonacci(2*i)); f(n) = if(n <= mx, fvec[n], fibonacci(2*n));
    is1(n) = {my(s = 0, m = n, k); while(m > 0, k = 1; while(m > f(k), k++); if(m < f(k), k--); if(m >= 2*f(k), s += 2; m -= 2*f(k), s++; m -= f(k))); !(n % s);}
    list(lim) = {my(q1 = is1(1), q2 = is1(2), q3 = is1(3), q4); for(k = 4, lim, q4 = is1(k); if(q1 && q2 && q3 && q4, print1(k-3, ", ")); q1 = q2; q2 = q3; q3 = q4);}

A364126 Starts of runs of 4 consecutive integers that are Stolarsky-Niven numbers (A364123).

Original entry on oeis.org

125340, 945591, 14998632, 16160505, 19304934, 42053801, 42064137, 46049955, 57180537, 103562368, 108489885, 122495982, 135562299, 139343337, 147991452, 164002374, 271566942, 296019657, 301748706, 310980030, 314537247, 316725570, 333478935, 336959907, 349815255
Offset: 1

Views

Author

Amiram Eldar, Jul 07 2023

Keywords

Comments

Are there runs of 5 or more consecutive integers that are Stolarsky-Niven numbers?

Crossrefs

Programs

  • Mathematica
    seq[2, 4] (* generates the first 2 terms, using the function seq[count, nConsec] from A364124 *)
  • PARI
    lista(2, 4) \\ generates the first 2 terms, using the function lista(count, nConsec) from A364124

A363792 Starts of runs of 4 consecutive integers that are primitive binary Niven numbers (A363787).

Original entry on oeis.org

8255214, 14673870, 29092590, 33185646, 41743854, 47697390, 48069486, 56348622, 56999790, 58116078, 59604462, 60534702, 60813774, 61837038, 62581230, 64069614, 64999854, 65371950, 66581262, 66674286, 75232494, 83418606, 86767470, 88069806, 92255886, 95418702, 96441966, 99511758, 99604782
Offset: 1

Views

Author

Amiram Eldar, Jun 22 2023

Keywords

Comments

There are no runs of 5 or more consecutive integers that are primitive binary Niven numbers (see the second comment in A330933).

Examples

			8255214 is a term since 8255214, 8255215, 8255216 and 8255217 are all primitive binary Niven numbers.
		

Crossrefs

Programs

  • Mathematica
    binNivQ[n_] := Divisible[n, DigitCount[n, 2, 1]]; primBinNivQ[n_] := binNivQ[n] && ! (EvenQ[n] && binNivQ[n/2]);
    seq[kmax_] := Module[{quad = primBinNivQ /@ Range[4], s = {}, k = 5}, While[k < kmax, If[And @@ quad, AppendTo[s, k - 4]]; quad = Join[Rest[quad], {primBinNivQ[k]}]; k++]; s]; seq[3*10^7]
  • PARI
    isbinniv(n) = !(n % hammingweight(n));
    isprim(n) = isbinniv(n) && !(!(n%2) && isbinniv(n/2));
    lista(kmax) = {my(quad = vector(4, i, isprim(i)), k = 5); while(k < kmax, if(vecsum(quad) == 4, print1(k-4, ", ")); quad = concat(vecextract(quad, "^1"), isprim(k)); k++); }

A364009 Starts of runs of 4 consecutive integers that are Wythoff-Niven numbers (A364006).

Original entry on oeis.org

374, 978, 17708, 832037, 1631097, 4821894, 5572377, 13376142, 14808759, 14930343, 35406720, 36534357, 38208519, 38748444, 38890509, 39088166, 65375232, 70046899, 79988116, 81224637, 82071105, 82898100, 94109430, 94875417, 95070492, 98014500, 100350522, 101651787, 102190437
Offset: 1

Views

Author

Amiram Eldar, Jul 01 2023

Keywords

Comments

Are there runs of 5 or more consecutive integers that are Wythoff-Niven numbers?

Crossrefs

Programs

  • Mathematica
    seq[3, 4] (* generates the first 3 terms using the function seq[count, nConsec] from A364007 *)

A331825 Positive numbers k such that -k, -(k + 1), -(k + 2), and -(k + 3) are 4 consecutive negative negabinary-Niven numbers (A331728).

Original entry on oeis.org

413, 2093, 3773, 4613, 7133, 7973, 8813, 10493, 11869, 15829, 16373, 23749, 30653, 31493, 34853, 35629, 37373, 39589, 40733, 49133, 51469, 54585, 55429, 63349, 64253, 65513, 67613, 70965, 75229, 91069, 98989, 102949, 103725, 106909, 110869, 114653, 129773, 131033
Offset: 1

Views

Author

Amiram Eldar, Jan 27 2020

Keywords

Crossrefs

Programs

  • Mathematica
    negaBinWt[n_] := negaBinWt[n] = If[n == 0, 0, negaBinWt[Quotient[n - 1, -2]] + Mod[n, 2]]; negaBinNivenQ[n_] := Divisible[n, negaBinWt[-n]]; nConsec = 4; neg = negaBinNivenQ /@ Range[nConsec]; seq = {}; c = 0; k = nConsec+1; While[c < 45, If[And @@ neg, c++; AppendTo[seq, k - nConsec]]; neg = Join[Rest[neg], {negaBinNivenQ[k]}]; k++]; seq

A338516 Starts of runs of 4 consecutive numbers that are divisible by the total binary weight of their divisors (A093653).

Original entry on oeis.org

1377595575, 4275143301, 13616091683, 13640596128, 15016388244, 15176619135, 21361749754, 23605084359, 24794290167, 28025464183, 29639590888, 30739547718, 33924433023, 35259630279, 38008366692, 38670247670, 38681191672, 40210059079, 40507412213, 49759198333, 52555068607
Offset: 1

Views

Author

Amiram Eldar, Oct 31 2020

Keywords

Comments

Can 5 consecutive numbers be divisible by the total binary weight of their divisors? If they exist, then they are larger than 10^11.

Examples

			1377595575 is a term since the 4 consecutive numbers from 1377595575 to 1377595578 are all terms of A093705.
		

Crossrefs

Subsequence of A338514 and A338515.
Similar sequences: A141769, A330933, A334372, A338454.

Programs

  • Mathematica
    divQ[n_] := Divisible[n, DivisorSum[n, DigitCount[#, 2, 1] &]]; div = divQ /@ Range[4]; Reap[Do[If[And @@ div, Sow[k - 4]]; div = Join[Rest[div], {divQ[k]}], {k, 5, 5*10^9}]][[2, 1]]
    SequencePosition[Table[If[Mod[n,Total[Flatten[IntegerDigits[#,2]&/@Divisors[n]]]]==0,1,0],{n,526*10^8}],{1,1,1,1}][[;;,1]] (* The program will take a long time to run. *) (* Harvey P. Dale, May 28 2023 *)
Previous Showing 11-19 of 19 results.