cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A362728 a(n) = [x^n] E(x)^n where E(x) = exp( Sum_{k >= 1} A108628(k-1)*x^k/k ).

Original entry on oeis.org

1, 1, 9, 91, 985, 11101, 128475, 1515032, 18116825, 218988046, 2669804209, 32776883899, 404733925435, 5022161428571, 62578069656776, 782560813918216, 9817011145746649, 123492956278927438, 1557295053170126994, 19681186581532094418
Offset: 0

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Author

Peter Bala, May 03 2023

Keywords

Comments

A108628(n) = B(n+1,n,n+1) in the notation of Straub, equation 24, where it is shown that the supercongruences A108628(n*p^k) == A108628(n*p^(k-1)) (mod p^(3*k)) hold for all primes p >= 5 and all positive integers n and k.
Inductively define a family of sequences {a(i,n) : n >= 0}, i >= 0, by setting a(0,n) = A108628(n) and, for i >= 1, a(i,n) = [x^n] ( exp(Sum_{k >= 1} a(i-1,k)*x^k/k) )^n. In this notation the present sequence is {a(1,n)}.
We conjecture that the sequences {a(i,n) : n >= 0}, i >= 1, satisfy the supercongruences u(n*p^r) == u(n*p^(r-1)) (mod p^(3*r)) for all primes p >= 7, and positive integers n and r.

Crossrefs

Programs

  • Maple
    A108628 := proc(n) add(binomial(n,k)*binomial(n+1,k)*binomial(n+k+1,k), k = 0..n) end:
    E(n,x) := series( exp(n*add(A108628(k-1)*x^k/k, k = 1..20)), x, 21 ):
    seq(coeftayl(E(n,x), x = 0, n), n = 0..20);

Formula

Conjecture: the supercongruence a(n*p^r) == a(n*p^(r-1)) (mod p^(3*r)) holds for all primes p >= 7 and positive integers n and r.

A362729 a(n) = [x^n] ( E(x)/E(-x) )^n where E(x) = exp( Sum_{k >= 1} A108628(k-1)*x^k/k ).

Original entry on oeis.org

1, 2, 8, 146, 1344, 18502, 214136, 2820834, 35377152, 465110894, 6038588808, 79936149174, 1056557893440, 14094461001558, 188319357861944, 2529143690991946, 34042038343081984, 459723572413090934, 6221522287903354568, 84397945280561045302, 1147007337762078241344
Offset: 0

Views

Author

Peter Bala, May 03 2023

Keywords

Comments

A108628(n) = B(n+1,n,n+1) in the notation of Straub, equation 24, where it is shown that the supercongruences A108628(n*p^k) == A108628(n*p^(k-1)) (mod p^(3*k)) hold for all primes p >= 5 and all positive integers n and k.

Crossrefs

Programs

  • Maple
    A108628 := proc(n) add(binomial(n,k)*binomial(n+1,k)*binomial(n+k+1,k) , k = 0..n) end:
    E(n,x) := series(exp(n*add(2*(A108628(2*k)*x^(2*k+1))/(2*k+1), k = 0..10)), x, 21):
    seq(coeftayl(E(n,x), x = 0, n), n = 0..20);

Formula

Conjecture:the supercongruence a(n*p^r) == a(n*p^(r-1)) (mod p^(3*r)) holds for all primes p >= 7 and positive integers n and r.

A362731 a(n) = [x^n] E(x)^n where E(x) = exp( Sum_{k >= 1} A000172(k)*x^k/k ).

Original entry on oeis.org

1, 2, 18, 182, 1954, 21702, 246366, 2839846, 33105186, 389264798, 4608481918, 54862022910, 656099844526, 7876525155020, 94867757934870, 1145843922848232, 13873839714404642, 168345900709550388, 2046612356962697502, 24923311881995950740, 303974276349311203854
Offset: 0

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Author

Peter Bala, May 05 2023

Keywords

Comments

It is known that the sequence of Franel numbers A000172 satisfies the Gauss congruences A000172(n*p^r) == A000172(n*p^(r-1)) (mod p^r) for all primes p and positive integers n and r.
One consequence is that the power series expansion of E(x) = exp( Sum_{k >= 1} A000172(k)*x^k/k ) = 1 + 2*x + 7*x^2 + 30*x^3 + 147*x^4 + ... (the g.f. of A166990) has integer coefficients (see, for example, Beukers, Proposition, p. 143). Therefore a(n) = [x^n] E(x)^n is an integer.
In fact, the Franel numbers satisfy stronger congruences than the Gauss congruences known as supercongruences: A000172(n*p^r) == A000172(n*p^(r-1)) (mod p^(3*r)) for all primes p >= 5 and positive integers n and r.

Crossrefs

Programs

  • Maple
    A000172 := proc(n) add(binomial(n,k)^3, k = 0..n); end:
    E(n,x) := series( exp(n*add(A000172(k)*x^k/k, k = 1..20)), x, 21 ):
    seq(coeftayl(E(n,x), x = 0, n), n = 0..20);

Formula

The Gauss congruence a(n*p^r) == a(n*p^(r-1)) (mod p^r) holds for all primes p and positive integers n and r.
Conjecture: the supercongruence a(n*p^r) == a(n*p^(r-1)) (mod p^(2*r)) holds for
all primes p and positive integers n and r.
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