A349482 Bases where the n-th Goodstein sequence starting in base 3 (instead of base 2) reaches 0.
4, 5, 7, 9, 11, 15, 19, 23, 63, 159, 2047, 10239, 49151, 1048575, 20971519, 402653183, 1180591620717411303423, 233840261972944466912589573234605283144949206876159
Offset: 1
Examples
For n=6, we write 6 = 2*3. Then in each step, we increase the base by 1, then subtract 1. This sequence goes 2*3 -> 1*4 + 3 -> 1*5 + 2 -> 1*6 + 1 -> 1*7 + 0 -> 0*8 + 7 ->...-> 0*14 + 1 -> 0*15, so 0 is reached at base 15.
Links
- Fine Design, Continue the sequence: 2, 4, 6, _? (BIGNUM BAKEOFF Part 2).
- Jonathan F. Waldmann, Goodstein sequences starting in base 3.
- Wikipedia, Goodstein's Theorem
Crossrefs
Cf. A056004.
Formula
For n<27, i.e. n = a*3^2 + b*3 + c with a, b, c < 3, a(n) = f_2^a (f_1^b (f_0^c (4) ) ) - 1.
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