A004748 Binary expansion contains 101.
5, 10, 11, 13, 20, 21, 22, 23, 26, 27, 29, 37, 40, 41, 42, 43, 44, 45, 46, 47, 52, 53, 54, 55, 58, 59, 61, 69, 74, 75, 77, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 101, 104, 105, 106, 107, 108, 109, 110, 111, 116, 117, 118, 119, 122
Offset: 1
Examples
20 is in the sequence because 20 = 10100_2. '10100' has '101' as one of its substrings. - _Indranil Ghosh_, Feb 11 2017
Links
- Indranil Ghosh, Table of n, a(n) for n = 1..50000
- Index entries for 2-automatic sequences.
Programs
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Mathematica
Select[Range[200], MemberQ[Partition[IntegerDigits[#, 2], 3, 1], {1, 0, 1}] &] (* Vincenzo Librandi, Feb 17 2018 *) Select[Range[200],SequenceCount[IntegerDigits[#,2],{1,0,1}]>0&] (* Requires Mathematica version 10 or later *) (* Harvey P. Dale, Jun 01 2020 *)
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PARI
is(n)=while(n>4,if(bitand(n,7)==5, return(1)); n>>=1); 0 \\ Charles R Greathouse IV, Feb 11 2017
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Python
i=j=0 while j<=100: if "101" in bin(i)[2:]: print(str(j)+" "+str(i)) j+=1 i+=1 # Indranil Ghosh, Feb 11 2017
Formula
a(n) ~ n. - Charles R Greathouse IV, Oct 23 2015
Extensions
Offset corrected by Charles R Greathouse IV, Feb 11 2017