A017510 a(n) = (11*n + 10)^2.

100, 441, 1024, 1849, 2916, 4225, 5776, 7569, 9604, 11881, 14400, 17161, 20164, 23409, 26896, 30625, 34596, 38809, 43264, 47961, 52900, 58081, 63504, 69169, 75076, 81225, 87616, 94249, 101124, 108241, 115600, 123201, 131044, 139129, 147456, 156025, 164836, 173889, 183184, 192721

Offset: 0

Author

N. J. A. Sloane

Keywords

• nonn
• easy

Links

• Harvey P. Dale, Table of n, a(n) for n = 0..1000
• Index entries for linear recurrences with constant coefficients, signature (3,-3,1).

Crossrefs

Powers of the form (11*n+10)^m: A017509 (m=1), this sequence (m=2), A017511 (m=3), A017512 (m=4), A017513 (m=5), A017514 (m=6), A017515 (m=7), A017516 (m=8), A017517 (m=9), A017518 (m=10), A017519 (m=11), A017520 (m=12).

Programs

GAP

List([0..40], n-> (11*n+10)^2); # G. C. Greubel, Oct 29 2019

Magma

[(11*n+10)^2: n in [0..40]]; // G. C. Greubel, Oct 29 2019

Maple

seq((11*n+10)^2, n=0..40); # G. C. Greubel, Oct 29 2019

Mathematica

(11*Range[0,40]+10)^2 (* or *) LinearRecurrence[{3,-3,1}, {100,441,1024}, 40] (* Harvey P. Dale, Mar 31 2016 *)

PARI

a(n)=(11*n+10)^2 \\ Charles R Greathouse IV, Jun 17 2017

Sage

[(11*n+10)^2 for n in (0..40)] # G. C. Greubel, Oct 29 2019

Formula

From G. C. Greubel, Oct 29 2019: (Start)

G.f.: (100 + 141*x + x^2)/(1-x)^3.

E.g.f.: (100 + 341*x + 121*x^2)*exp(x). (End)