A047335 Numbers that are congruent to {0, 6} mod 7.
0, 6, 7, 13, 14, 20, 21, 27, 28, 34, 35, 41, 42, 48, 49, 55, 56, 62, 63, 69, 70, 76, 77, 83, 84, 90, 91, 97, 98, 104, 105, 111, 112, 118, 119, 125, 126, 132, 133, 139, 140, 146, 147, 153, 154, 160, 161, 167, 168
Offset: 1
References
- Hsien-Kuei Hwang, S Janson, TH Tsai, Exact and asymptotic solutions of the recurrence f(n) = f(floor(n/2)) + f(ceiling(n/2)) + g(n): theory and applications, Preprint, 2016; http://140.109.74.92/hk/wp-content/files/2016/12/aat-hhrr-1.pdf. Also Exact and Asymptotic Solutions of a Divide-and-Conquer Recurrence Dividing at Half: Theory and Applications, ACM Transactions on Algorithms, 13:4 (2017), #47; DOI: 10.1145/3127585
Links
- Index entries for linear recurrences with constant coefficients, signature (1, 1, -1).
Crossrefs
Cf. A274406.
Programs
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Mathematica
Select[Range[0,200],MemberQ[{0,6},Mod[#,7]]&] (* Harvey P. Dale, Mar 16 2011 *)
Formula
From Bruno Berselli, Oct 06 2010: (Start)
G.f.: x^2*(6+x)/((1+x)*(1-x)^2).
a(n) - a(n-1) - a(n-2) + a(n-3) = 0 (n > 3).
a(n) = (14*n + 5*(-1)^n - 9)/4.
a(n) - a(n-2) = 7 (n > 2).
a(n) - a(n-1) = A010687(k) with n > 1 and k == n-1 (mod 2). (End)
a(n+1) = Sum_{k>=0} A030308(n,k)*b(k) with b(0)=6 and b(k) = 7*2^(k-1) = A005009(k-1) for k > 0. - Philippe Deléham, Oct 18 2011