A056154 Numbers n such that the number of times each digit occurs in 2^n, represented in base 3, is the same as 2^(n+1), also represented in base 3. Or in other words, when represented in base 3, the digits in 2^n can be rearranged to form 2^(n+1).
5, 27, 40, 92, 138, 929, 1086, 352664, 4976816, 9914261, 23434996, 30490425, 49094174
Offset: 1
Examples
First term: 2^5 = 1012 and 2^6 = 2101 -> number of occurrences of 0, 1 and 2 are {1 2 1}; second term: 2^27 = 100100112222002222 and 2^28 = 200201002221012221 -> {6 4 8}.
Links
- J. Frech, Extending A056154, 2019.
Extensions
More terms from Bruce G. Stewart (bstewart(AT)bix.com), Aug 28 2000 and Sep 15 2000
a(13) from Jonathan Frech, Oct 31 2019
Comments