cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A060309 A001067 appears to count the periodic points for a certain map. If so, then this is the sequence of the numbers of orbits of length n.

Original entry on oeis.org

1, 0, 0, 0, 0, 115, 0, 452, 4874, 17461, 7062, 19696950, 50610, 242341439, 114877883680, 481832564850, 8919335150, 1461959530725195586, 8116326631140, 13054135924822447372, 72385602091336704890, 115013510658268698717, 1127506827209663824722
Offset: 1

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Author

Thomas Ward, Apr 10 2001

Keywords

Examples

			a(11) = 7062 because the 11th term of A001067 is 77683 and the first term is 1, so there should be (77683-1)/11 = 7062 orbits of length 11.
		

Crossrefs

Formula

If b(n) is the n-th term of A001067, then a(n)=(1/n)* |Sum_{d|n}mu(d)b(n/d)|, n<>2.

Extensions

a(18) corrected and more terms from Sean A. Irvine, Nov 08 2022

A060334 The sequence A006863 (shifted by one) seems to be counting the periodic points for a map. If so, then this is the sequence of the numbers of orbits of length n.

Original entry on oeis.org

24, 108, 160, 60, 48, 10800, 0, 1980, 3136, 1272, 48, 5440, 0, 480, 11408, 1020, 0, 7671552, 0, 53448, 7200, 216, 48, 179520, 0, 480, 2128, 240, 48, 227138600, 0
Offset: 1

Views

Author

Thomas Ward, Apr 10 2001

Keywords

Examples

			a(3) = 160 because the 4th term of A006863 is 504 and the 2nd term is 24, so there should be (504-24)/3 = 160 orbits of length 3.
		

Crossrefs

Formula

If b(n) is the (n+1)st term of A006863, then a(n)=(1/n)* Sum_{d|n}\mu(d)b(n/d)
Showing 1-2 of 2 results.