A061065 -id:A061065 - cp's OEIS frontend

A210356 Maximum modulus in the inverse of Hilbert's matrix.

1, 12, 192, 6480, 179200, 4410000, 133402500, 4249941696, 122367445200, 3480673996800, 117643011932160, 3659449159080000, 106518477825760000, 3521767173114190000, 114708987924290760000, 3525270042097046880000, 110552468520163390156800

Offset: 1

T. D. Noe, Mar 28 2012

nonn

This sequence corrects A061065, which was wrong for n > 6. These values appear at the A210357(n) position on the diagonal. Thanks to Clark Kimberling for verifying this sequence.

T. D. Noe, Table of n, a(n) for n = 1..100

Cf. A061065, A189765 (inverse matrix), A210357, A210358 (minimum).

Table[im = Inverse[HilbertMatrix[n]]; Max[Abs[Flatten[im]]], {n, 20}]

for(n=1,17, my(h=1/mathilbert(n),s=0); for(j=1,n, for(k=1,n, s=max(s,h[j,k]))); print1(s,", ")) \\ Hugo Pfoertner, Feb 11 2020

A210358 Minimum value in the inverse of Hilbert's matrix.

Original entry on oeis.org

1, -6, -180, -4200, -117600, -3969000, -115259760, -3030051024, -106051785840, -3363975014400, -98227319533200, -3110531785218000, -103492384705710000, -3211851661880141280, -96355549856404238400, -3303308595002047632000, -106681852579497947388000

Offset: 1

T. D. Noe, Apr 02 2012

sign

T. D. Noe, Table of n, a(n) for n = 1..100

Cf. A061065, A189765 (inverse matrix), A210357.

Table[im = Inverse[HilbertMatrix[n]]; Min[Flatten[im]], {n, 20}]

a(n)=vecmin(1/mathilbert(n)) \\ Hugo Pfoertner, Feb 11 2020

cp's OEIS Frontend

A210356 Maximum modulus in the inverse of Hilbert's matrix.

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