A064931 Numbers m such that the digits of m are also digits of m^3.

1, 4, 5, 6, 9, 10, 11, 12, 21, 24, 25, 29, 32, 33, 34, 39, 40, 49, 50, 51, 54, 56, 59, 60, 61, 64, 65, 67, 71, 72, 73, 75, 76, 90, 97, 99, 100, 101, 102, 106, 109, 110, 114, 119, 120, 124, 125, 129, 137, 153, 176, 201, 202, 210, 212, 224, 228, 231, 233, 236

Offset: 1

Author

Joseph L. Pe, Feb 14 2002

Keywords

• nonn
• base

Comments

Presumably if a digit d appears k times in m, then it should appear at least k times in m^3. - N. J. A. Sloane, Nov 24 2018

Examples

			12^3 = 1728, which contains all digits of 12, so 12 is a term of the sequence.
		

Links

• Harvey P. Dale, Table of n, a(n) for n = 1..1000

Crossrefs

Cf. A029776.

Programs

Mathematica

Select[Range[400],Min[DigitCount[#^3]-DigitCount[#]]>-1&] (* Harvey P. Dale, Nov 24 2018 *)

Extensions

Corrected and Mathematica program replaced by Harvey P. Dale, Nov 24 2018