A065482 a(n) = round( 2^n/n ).
2, 2, 3, 4, 6, 11, 18, 32, 57, 102, 186, 341, 630, 1170, 2185, 4096, 7710, 14564, 27594, 52429, 99864, 190650, 364722, 699051, 1342177, 2581110, 4971027, 9586981, 18512790, 35791394, 69273666, 134217728, 260301048, 505290270, 981706811, 1908874354, 3714566310
Offset: 1
Keywords
Links
- Harry J. Smith, Table of n, a(n) for n = 1..300
Programs
-
Magma
[Round(2^n/n): n in [1..30]]; // G. C. Greubel, Jan 18 2018
-
Mathematica
Table[Floor[(Floor[n/2]+2^n)/n], {n, 1, 100}]
-
PARI
a(n) = { round(2^n/n) } \\ Harry J. Smith, Oct 20 2009
-
Python
def A065482(n): return ((1<
>1))//n # Chai Wah Wu, Apr 23 2025
Formula
a(n) = A082894(n)/n.
a(n) = floor((2^n + floor(n/2))/n).