A065714 Number of 3's in decimal expansion of 2^n.
0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 0, 0, 0, 0, 1, 1, 0, 3, 0, 1, 1, 1, 1, 1, 0, 1, 0, 4, 1, 3, 0, 1, 0, 1, 1, 1, 0, 3, 1, 3, 0, 2, 0, 1, 2, 0, 1, 2, 2, 0, 2, 3, 0, 4, 1, 3, 1, 4, 2, 1, 1, 1, 2, 3, 2, 3, 1, 2, 4, 1, 4, 3, 0, 3, 2, 3, 4, 4, 3, 3, 2, 1, 3, 0, 0, 4, 2, 2, 6, 1, 4, 4, 2
Offset: 0
Examples
2^5 = 32 so a(5)=1.
Links
- Harry J. Smith, Table of n, a(n) for n = 0..1000
Crossrefs
Programs
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Mathematica
Table[ Count[ IntegerDigits[2^n], 3], {n, 0, 100} ]
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PARI
a(n) = #select(x->(x==3), digits(2^n)); \\ Michel Marcus, Jun 15 2018
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Python
def A065714(n): return str(2**n).count('3') # Chai Wah Wu, Feb 14 2020
Extensions
More terms from Robert G. Wilson v, Dec 07 2001
Comments