A065775 Array T read by diagonals: T(i,j)=least number of knight's moves on a chessboard (infinite in all directions) needed to move from (0,0) to (i,j).
0, 3, 3, 2, 2, 2, 3, 1, 1, 3, 2, 2, 4, 2, 2, 3, 3, 3, 3, 3, 3, 4, 4, 2, 2, 2, 4, 4, 5, 3, 3, 3, 3, 3, 3, 5, 4, 4, 4, 4, 4, 4, 4, 4, 4, 5, 5, 5, 3, 3, 3, 3, 5, 5, 5, 6, 6, 4, 4, 4, 4, 4, 4, 4, 6, 6, 7, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 7, 6, 6, 6, 6, 4, 4, 4, 4, 4, 6, 6, 6, 6, 7, 7, 7, 5, 5, 5, 5, 5, 5, 5, 5, 7, 7, 7
Offset: 0
Examples
From _Clark Kimberling_, Dec 20 2010: (Start) T(i,j) for -2<=i<=2 and -2<=j<=2: 4 1 2 1 4=T(2,2) 1 2 3 2 1=T(2,1) 2 3 0 3 2=T(2,0) 1 2 3 2 1=T(2,-1) 4 1 2 1 4=T(2,-2) Corner of the array, T(i,j) for i>=0, j>=0: [Corrected Oct 14 2016] 0 3 2 3 2 3 4... 3 2 1 2 3 4 3... 2 1 4 3 2 3 4... 3 2 3 2 3 4 2... (End)
Crossrefs
Formula
From Clark Kimberling, Dec 20 2010: (Start)
T(i,j) is given in cases:
Case 1: row 0
T(0,0)=0, T(1,0)=3, and for m>=1,
T(4m-2,0)=2m, T(4m-1,0)=2m+1, T(4m,0)=2m,
T(4m+1,0)=2m+1.
Case 2: row 1
T(0,1)=3, T(1,1)=2, and for m>=1,
T(4m-2,1)=2m-1, T(4m-1,1)=2m, T(4m,1)=2m+1,
T(4m+1,1)=2m+2.
Case 3: columns 0 and 1
(column 0 = row 0); (column 1 = row 1).
Case 4: For i>=2 and j>=2,
T(i,j)=1+min{T(i-2,j-1),T(i-1,j-2)}.
Cases 1-4 determine T in the 1st quadrant;
all other T(i,j) are easily obtained by symmetry. (End)