A067770 a(n) = Catalan(n) mod (n+2).
1, 1, 2, 0, 2, 0, 4, 6, 0, 0, 8, 0, 0, 10, 8, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 18, 0, 0, 20, 0, 16, 22, 0, 0, 12, 0, 0, 13, 0, 0, 14, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 32, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 54, 0, 0, 56, 0, 0, 58, 0, 0
Offset: 0
Keywords
Links
- Alois P. Heinz, Table of n, a(n) for n = 0..10000
Programs
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Maple
a:= n-> binomial(2*n, n)/(n+1) mod (n+2): seq(a(n), n=0..88);
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Mathematica
Table[Mod[CatalanNumber[n],n+2],{n,0,90}] (* Harvey P. Dale, Mar 06 2025 *)
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PARI
for(k=0,80,print1(binomial(2*k,k)/(k+1)%(k+2),", ")) \\ Hugo Pfoertner, Jul 16 2020
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Python
A067770_list, c = [1,1], 1 for n in range(2,10001): c = c*(4*n-2)//(n+1) A067770_list.append(c % (n+2)) # Chai Wah Wu, Jul 16 2020
Extensions
Name corrected by Hugo Pfoertner, Jul 16 2020