A069951 Continued fraction expansion of the number e^(2/3).
1, 1, 18, 7, 1, 1, 10, 54, 16, 1, 1, 19, 90, 25, 1, 1, 28, 126, 34, 1, 1, 37, 162, 43, 1, 1, 46, 198, 52, 1, 1, 55, 234, 61, 1, 1, 64, 270, 70, 1, 1, 73, 306, 79, 1, 1, 82, 342, 88, 1, 1, 91, 378, 97, 1, 1, 100, 414, 106, 1, 1, 109, 450, 115, 1, 1, 118, 486, 124, 1, 1, 127, 522
Offset: 0
Links
- G. Xiao, Contfrac
- K. Matthews, Finding the continued fraction of e^(l/m)
Programs
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Mathematica
ContinuedFraction[ E^(2/3), 100]
Formula
If k>0 a(5k)=a(5k+1)=1, a(5k+2)=9k+1, a(5k+3)=36k+18, a(5k+4)=9k+7. - Benoit Cloitre, May 04 2002
Extensions
Edited and extended by Robert G. Wilson v and Benoit Cloitre, May 04 2002
Comments