A070266 Maximum element in the simple continued fraction expansion of H(n) = 1+1/2+1/3+...+1/n, the n-th harmonic number.
1, 2, 5, 12, 8, 4, 5, 7, 7, 13, 50, 15, 6, 39, 43, 9, 14, 61, 25, 17, 36, 13, 5, 17, 18, 20, 68, 45, 25, 198, 88, 1090, 120, 244, 29, 29, 24, 111, 567, 22, 20, 37, 1812, 59, 41, 336, 121, 32, 37, 314, 104, 162, 289, 146, 1557, 42, 78, 639, 52, 812, 116, 32, 131, 236, 59
Offset: 1
Examples
The simple continued fraction expansion of H(10) is [2, 1, 13, 12, 1, 3, 1, 2], hence a(10) = 13.
Links
- Amiram Eldar, Table of n, a(n) for n = 1..10000
Programs
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Mathematica
Table[ Max[ ContinuedFraction[ HarmonicNumber[n]]], {n, 1, 65}]