cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-3 of 3 results.

A092910 a(n) is the (3n+2)-th component of the continued fraction for sum(k>=0,2^(-k!)).

Original entry on oeis.org

3, 4, 3, 3, 2, 3, 4, 3, 2, 4, 3, 2, 3, 3, 4, 3, 2, 4, 3, 3, 2, 3, 4, 2, 3, 4, 3, 2, 3, 3, 4, 3, 2, 4, 3, 3, 2, 3, 4, 3, 2, 4, 3, 2, 3, 3, 4, 2, 3, 4, 3, 3, 2, 3, 4, 2, 3, 4, 3, 2, 3, 3, 4, 3, 2, 4, 3, 3, 2, 3, 4, 3, 2, 4, 3, 2, 3, 3, 4, 3, 2, 4, 3, 3, 2, 3, 4, 2, 3, 4, 3, 2, 3, 3, 4, 2, 3, 4, 3, 3, 2, 3, 4, 3, 2
Offset: 0

Views

Author

Benoit Cloitre, Apr 16 2004

Keywords

Crossrefs

Programs

  • PARI
    a(n)=5-component(contfrac(sum(i=0,10,1/2^(2^i))),n+3)/2
    
  • Scheme
    (define (A092910 n) (- 5 (* 1/2 (A007400 (+ 2 n))))) ;;  Code for A007400 given under that entry. - Antti Karttunen, Aug 12 2017

Formula

a(n) = 5 - (A007400(n+2)/2).

A076152 Let c = Sum_{k>=0} 1/2^(k!). Sequence gives values of terms not congruent to 5 in the continued fraction for c.

Original entry on oeis.org

1, 3, 1, 3, 4, 1, 3, 3, 1, 3, 1, 2, 1, 3, 3, 1, 4, 3, 1, 3, 1, 2, 1, 3, 4, 1, 3, 3, 1, 2, 1, 3, 1, 3, 3, 1, 4, 3, 1, 3, 1, 2, 1, 3, 4, 1, 3, 3, 1, 3, 1, 2, 1, 3, 3, 1, 4, 3, 1, 2, 1, 3, 1, 3, 4, 1, 3, 3, 1, 2, 1, 3, 1, 3, 3, 1, 4, 3, 1, 3, 1, 2, 1, 3, 4, 1, 3, 3, 1, 3, 1, 2, 1, 3, 3, 1, 4, 3, 1, 3, 1, 2, 1, 3, 4
Offset: 1

Views

Author

Benoit Cloitre, Nov 02 2002

Keywords

Comments

Appears to contain only 1,2,3 or 4; seems to be a pseudo-periodic sequence.

Examples

			The continued fraction for c is shown in A076157. "Big terms" are all congruent to 5.
		

Crossrefs

A076154 Let c = Sum_{k>=0} 1/2^(k!), sequence gives values of terms congruent to 5 of the continued fraction for c.

Original entry on oeis.org

4095, 4722366482869645213695, 4095, 3121748550315992231381597229793166305748598142664971150859156959625371738819765620120306103063491971159826931121406622895447975679288285306290175, 4095, 4722366482869645213695, 4095
Offset: 1

Views

Author

Benoit Cloitre, Nov 02 2002

Keywords

Comments

Observation: if b(k) denotes the sequence of all elements of the continued fraction for c, b(k)=4095 if k==6 or 19 (mod 24); b(k)=4722366482869645213695 if k==12 or 37 (mod 48) ...

Examples

			The continued fraction for c is shown in A076157. The "big terms" are all congruent to 5.
		

Crossrefs

Formula

It seems that for n>=1, a(2n-1)=4095; a(4n-2)=4722366482869645213695 etc.
Showing 1-3 of 3 results.