A076634 Coefficient of x^a(n) in (x+1/2)*(x+2/2)*...*(x+n/2) is the largest one.
1, 1, 2, 2, 2, 2, 3, 3, 3, 3, 3, 3, 3, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7
Offset: 1
Keywords
Crossrefs
Cf. A076620.
Programs
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PARI
a(n) = my(p=prod(j=1, n, x+j/2), m=vecmax(Vec(p))); for (i=0, poldegree(p), if (polcoef(p, i)==m, return(i))); \\ Michel Marcus, Feb 19 2021
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Python
from sympy import prod, Poly from sympy.abc import x def A076634(n): y = Poly(prod(2*x+i for i in range(1,n+1))).all_coeffs()[::-1] return y.index(max(y)) # Chai Wah Wu, Mar 07 2021