A079399 Number of dots in Braille representation of n.

3, 1, 2, 2, 3, 2, 3, 4, 3, 2, 4, 2, 3, 3, 4, 3, 4, 5, 4, 3, 5, 3, 4, 4, 5, 4, 5, 6, 5, 4, 5, 3, 4, 4, 5, 4, 5, 6, 5, 4, 6, 4, 5, 5, 6, 5, 6, 7, 6, 5, 5, 3, 4, 4, 5, 4, 5, 6, 5, 4, 6, 4, 5, 5, 6, 5, 6, 7, 6, 5, 7, 5, 6, 6, 7, 6, 7, 8, 7, 6, 6, 4, 5, 5, 6, 5, 6, 7, 6, 5, 5, 3, 4, 4, 5, 4, 5, 6, 5, 4

Offset: 0

Author

Jon Perry, Feb 16 2003

Keywords

• nonn

Comments

The number of dots in [0..9] is [3,1,2,2,3,2,3,4,3,2].

Examples

			a(11) = 1+1 = 2.
		

Links

• American Foundation for the Blind, Braille Bug
• American Printing House for the Blind, Braille: Deciphering the Code
• RNIB, This is Braille

Crossrefs

See A072283 for another version. Cf. A079401, A079405.

Cf. A000120, A121018, A121019.

Programs

Mathematica

With[{br=Thread[Range[0,9]->{3,1,2,2,3,2,3,4,3,2}]},Total/@ Table[ IntegerDigits[ n]/.br,{n,0,100}]] (* Harvey P. Dale, May 24 2013 *)

PARI

{ braille=[3,1,2,2,3,2,3,4,3,2]; for (n=0,99, b=braille[n%10+1]; if (n>9,b=b+braille[n\10+1]); print1(b",")) }

Python

b = [3, 1, 2, 2, 3, 2, 3, 4, 3, 2]
def a(n): return sum(b[d] for d in map(int, str(n)))
print([a(n) for n in range(100)]) # Michael S. Branicky, Mar 01 2021

Formula

a(n) = A000120(A121018(n)) = A000120(A121019(n)). - Reinhard Zumkeller, Jul 23 2006