cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A079896 Discriminants of indefinite binary quadratic forms.

Original entry on oeis.org

5, 8, 12, 13, 17, 20, 21, 24, 28, 29, 32, 33, 37, 40, 41, 44, 45, 48, 52, 53, 56, 57, 60, 61, 65, 68, 69, 72, 73, 76, 77, 80, 84, 85, 88, 89, 92, 93, 96, 97, 101, 104, 105, 108, 109, 112, 113, 116, 117, 120, 124, 125, 128, 129, 132, 133, 136, 137, 140, 141, 145, 148
Offset: 1

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Author

Wolfdieter Lang, Jan 31 2003

Keywords

Comments

Numbers n such that n == 0 (mod 4) or n == 1 (mod 4), but n is not a square.
For an indefinite binary quadratic form over the integers a*x^2 + b*x*y + c*y^2 the discriminant is D = b^2 - 4*a*c > 0; and D not a square is assumed.
Also, a superset of A227453. - Ralf Stephan, Sep 22 2013
For the period length of the continued fraction of sqrt(a(n)) see A267857(n). - Wolfdieter Lang, Feb 18 2016
[I changed the offset to 1, since this is an important list. Many parts of the entry, including the b-file, will need to be changed. - N. J. A. Sloane, Mar 14 2023]

References

  • McMullen, Curtis. "Billiards and Teichmüller curves." Bulletin of the American Mathematical Society, 60:2 (2023), 195-250. See Table C.1.
  • A. Scholz and B. Schoeneberg, Einführung in die Zahlentheorie, 5. Aufl., de Gruyter, Berlin, New York, 1973, p. 112.

Crossrefs

Cf. A014601, A042948 (with squares), A087048 (class numbers), A267857.

Programs

  • Mathematica
    Select[ Range[148], (Mod[ #, 4] == 0 || Mod[ #, 4] == 1) && !IntegerQ[ Sqrt[ # ]] & ]
  • PARI
    seq(N) = {
      my(n = 1, v = vector(N), top = 0);
      while (top < N,
        if (n%4 < 2 && !issquare(n), v[top++] = n); n++;);
      return(v);
    };
    seq(62) \\ Gheorghe Coserea, Nov 07 2016

Formula

a(2*k^2 + 2*k + 1) = 4*(k+1)^2 + 1 for k >= 0. - Gheorghe Coserea, Nov 07 2016
a(2*k^2 + 4*k + 2 + (k+1)*(-1)^k) = (2*k + 3)*(2*k + 3 + (-1)^k) for k >= 0. - Bruno Berselli, Nov 10 2016

Extensions

More terms from Robert G. Wilson v, Mar 26 2003
Offset changed to 1 (since this is a list). - N. J. A. Sloane, Mar 14 2023