A080509 Last term in n-th row of A080508.
1, 4, 4, 216, 324, 6075000, 30375000, 750453558750000, 19699405917187500, 459652804734375000, 9652708899421875000, 578346405423301688948883281250000, 111331683043985575122660031640625000, 77892265302487151682927242578030755976166730468750000
Offset: 1
Keywords
Examples
For n=5, first four terms of row are 1, 2, 3, 4, with product 24 = 2^3*3^1. So last term is 2^(5-3)*3^(5-1) = 2^2*3^4 = 324.
Links
- Jeppe Stig Nielsen, Table of n, a(n) for n = 1..54
Crossrefs
Cf. A080508.
Programs
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Mathematica
MapAt[4 # &, Array[Apply[Times, Prime@ Range@ PrimePi[# - 1]]^#/(# - 1)! &, 14], 2] (* Michael De Vlieger, Nov 05 2018 *)
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PARI
a(n) = {if (n == 1, return (1)); if (n == 2, return (2^2)); f = factor((n-1)!); prod(i = 1, #f~, f[i,1]^(n - f[i,2]));} \\ Michel Marcus, Aug 30 2013
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PARI
a(n) = if(n==2, 4, prod(i=1,primepi(n-1),prime(i))^n/(n-1)!) \\ Jeppe Stig Nielsen, Nov 04 2018
Formula
For n!=2, a(n) = (A034386(n - 1))^n / (n - 1)!. - Jeppe Stig Nielsen, Nov 04 2018
Extensions
More terms from Michel Marcus, Aug 30 2013