cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-4 of 4 results.

A137686 a(n) = Bigomega(Catalan(n)) - round( 3 n /(2 log(n+2))) (= A081399 - A137687).

Original entry on oeis.org

0, -1, -1, -2, -1, -1, 0, -2, -1, -2, -1, -1, -1, 0, 1, -1, 0, -1, 1, 0, 0, 0, 1, 0, 0, 1, 0, -1, 1, 0, 1, -2, -1, 0, 0, -2, -1, -1, 1, -1, 0, 2, 2, 2, 2, 1, 3, 1, 2, 0, 2, 1, 1, 1, 1, -1, -1, -1, 1, 0, 2, 3, 3, 0, 0, 0, 1, 0, 3, 2, 2, 0, 2, 3, 3, 2, 2, 3, 4, 1, 0, 1, 1, 1, 1, 1, 3, 1, 4, 2, 2, 1, 2, 2, 3, 2, 3, 1, 2, 0, 1, 0, 2, 1, 2, 2, 3, 1, 3, 2, 3, 1, 2, 3, 3, 2, 3
Offset: 0

Views

Author

M. F. Hasler, Feb 06 2008

Keywords

Comments

It is easy to show that A081399(n) = bigomega(Catalan(n)) is between n/log(n) and 2n/log(n) (for n>n0). The sequence A137687 is roughly the middle of this interval, which turns out to be a fair approximation to A081399. The present sequence lists the (signed) difference.

Crossrefs

Programs

  • PARI
    A137686(n) = bigomega(prod(i=2,n,(n+i)/i)) - round(3*n/log(n+2)/2)

Formula

a(n) = A001222(A000108(n)).

A137687 a(n) = round(3 n / (2 log(n+2))), an approximation to A081399.

Original entry on oeis.org

0, 1, 2, 3, 3, 4, 4, 5, 5, 6, 6, 6, 7, 7, 8, 8, 8, 9, 9, 9, 10, 10, 10, 11, 11, 11, 12, 12, 12, 13, 13, 13, 14, 14, 14, 15, 15, 15, 15, 16, 16, 16, 17, 17, 17, 18, 18, 18, 18, 19, 19, 19, 20, 20, 20, 20, 21, 21, 21, 22, 22, 22, 22, 23, 23, 23, 23, 24, 24, 24, 25, 25, 25, 25, 26, 26
Offset: 0

Views

Author

M. F. Hasler, Feb 06 2008

Keywords

Comments

It is easy to show that A081399(n) is between n/log(n) and 2n/log(n) (for n>n0), cf. [Campbell 1984]. This sequence A137687 is roughly the middle of this interval (with log(n) replaced by log(n+2) to be well-defined for all n>=0), which turns out to be a fair (and simple, increasing) approximation for A081399.
See A137686 for the (signed) difference of the two sequences.

Crossrefs

Programs

A080405 Number of distinct primes dividing n-th Catalan number.

Original entry on oeis.org

0, 0, 1, 1, 2, 3, 3, 3, 4, 4, 4, 5, 5, 5, 6, 6, 7, 8, 8, 9, 9, 9, 9, 9, 9, 9, 9, 10, 11, 11, 11, 11, 12, 13, 13, 13, 13, 13, 13, 14, 14, 15, 15, 15, 16, 16, 16, 17, 17, 17, 17, 17, 17, 19, 18, 18, 18, 18, 19, 19, 20, 20, 20, 20, 21, 22, 22, 23, 22, 22, 22, 23, 23, 23, 24, 24, 25, 25
Offset: 0

Views

Author

Labos Elemer, Mar 19 2003

Keywords

Examples

			a(5) = 3, as C(5) = 42 factors as 2*3*7 (3 distinct prime factors).
		

Crossrefs

Programs

  • Mathematica
    PrimeNu[CatalanNumber[Range[0,80]]] (* Harvey P. Dale, Mar 27 2013 *)
  • PARI
    C(n)=binomial(2*n,n)/(n+1);
    for(n=1,100,print1(matsize(factor(C(n-1)))[1],", ")); \\ Joerg Arndt, Apr 19 2014

Formula

a(n) = A001221(A000108(n)).

A121612 Numbers k such that the number of prime divisors of the k-th Catalan number (counted with multiplicity) divides k.

Original entry on oeis.org

2, 3, 4, 8, 10, 12, 16, 20, 22, 117, 408, 432, 444, 492, 504, 508, 1555, 1560, 1605, 1675, 1790, 5832, 5940, 5976, 6048, 6078, 6102, 6108, 6132, 6138, 21175, 21266, 21280, 21301, 21434, 21462, 21469, 21616, 21623, 21749, 21770, 21784, 81472, 81528, 81648
Offset: 1

Views

Author

Jonathan Vos Post, Sep 08 2006

Keywords

Comments

a(46) > 200000, if it exists. - Amiram Eldar, Oct 10 2024

Examples

			a(1) = 2 because bigomega(Catalan(2)) = bigomega(2) = 1 and 1 | 2.
		

Crossrefs

Programs

  • Mathematica
    fQ[n_] := Mod[n, Plus @@ (Last@# & /@ FactorInteger[ Binomial[2n, n]/(n + 1)])] == 0; s = {}; Do[ If[fQ@n, Print@n; AppendTo[s, n]], {n, 2, 35500}] (* Robert G. Wilson v, Sep 11 2006 *)

Formula

{k such that A081399(k)|k} = {k such that A001222(A000108(k))|k}.

Extensions

Corrected and extended (a(10)-a(42)) by Robert G. Wilson v, Sep 11 2006
a(43)-a(45) from Amiram Eldar, Oct 10 2024
Showing 1-4 of 4 results.