cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-3 of 3 results.

A083075 Square array read by antidiagonals: T(n,k) = (k*(2*k+3)^n + 1)/(k+1).

Original entry on oeis.org

1, 1, 1, 1, 3, 1, 1, 5, 13, 1, 1, 7, 33, 63, 1, 1, 9, 61, 229, 313, 1, 1, 11, 97, 547, 1601, 1563, 1, 1, 13, 141, 1065, 4921, 11205, 7813, 1, 1, 15, 193, 1831, 11713, 44287, 78433, 39063, 1, 1, 17, 253, 2893, 23801, 128841, 398581, 549029, 195313, 1, 1, 19, 321
Offset: 0

Views

Author

Paul Barry, Apr 23 2003

Keywords

Examples

			Array begins:
  1     1     1     1     1 ...
  1     3    13    63   313 ...
  1     5    33   229  1601 ...
  1     7    61   547  4921 ...
  1     9    97  1065 11713 ...
  ...
		

Crossrefs

Columns include odds, A082109, A083079.
Diagonals include A083079, A083080, A083081, A083082.

Programs

  • Maple
    T := proc(n,k) return (k*(2*k+3)^n+1)/(k+1): end: seq(seq(T(k,n-k),k=0..n),n=0..10); # Nathaniel Johnston, Jun 26 2011

A083082 First subdiagonal of number array A083075.

Original entry on oeis.org

1, 5, 61, 1065, 23801, 650893, 21120373, 794552657, 34040573425, 1637411510421, 87420145670573, 5131440522974329, 328542298690792681, 22789709877615373085, 1702810951672313083621, 136361486383932674632353
Offset: 0

Views

Author

Paul Barry, Apr 23 2003

Keywords

Crossrefs

Programs

  • Magma
    [((n+1)*(2*n+5)^n+1)/(n+2): n in [0..20]]; // Vincenzo Librandi, Nov 12 2011
  • Mathematica
    Table[((n+1)(2n+5)^n+1)/(n+2),{n,0,20}] (* Harvey P. Dale, Oct 06 2019 *)

Formula

a(n) = ((n+1)*(2n+5)^n + 1)/(n+2).

A083081 First superdiagonal of number array A083075.

Original entry on oeis.org

1, 13, 229, 4921, 128841, 4022341, 146450893, 6103787761, 286833509137, 15011892880381, 866190689012661, 54637591044108073, 3740820141248285785, 276304073198956644661, 21900911192388373534621
Offset: 1

Views

Author

Paul Barry, Apr 23 2003

Keywords

Crossrefs

Programs

Formula

a(n) = ((n-1)*(2n+1)^n + 1)/n.
Showing 1-3 of 3 results.