A083822 a(n) = digit reversal of 3*n, divided by 3.
1, 2, 3, 7, 17, 27, 4, 14, 24, 1, 11, 21, 31, 8, 18, 28, 5, 15, 25, 2, 12, 22, 32, 9, 19, 29, 6, 16, 26, 3, 13, 23, 33, 67, 167, 267, 37, 137, 237, 7, 107, 207, 307, 77, 177, 277, 47, 147, 247, 17, 117, 217, 317, 87, 187, 287, 57, 157, 257, 27, 127, 227, 327, 97, 197, 297, 34
Offset: 1
Examples
a(25) = reverse(3*25)/3 = reverse(75)/3 = 57/3 = 19.
Links
- Harvey P. Dale, Table of n, a(n) for n = 1..1000
Programs
-
Mathematica
Table[FromDigits[Reverse[IntegerDigits[3n]]]/3,{n,70}] (* Harvey P. Dale, May 19 2015 *) IntegerReverse[3*Range[70]]/3 (* Harvey P. Dale, Apr 12 2022 *)
-
PARI
{for(n=1,70,k=3*n; rev=0; while(k>0,d=divrem(k,10); k=d[1]; rev=10*rev+d[2]); print1(rev/3,","))}
-
PARI
apply( A083822(n)=fromdigits(Vecrev(digits(3*n)))/3, [0..99]) \\ M. F. Hasler, May 21 2021
Extensions
Edited, corrected and extended by Klaus Brockhaus, May 11 2003
Comments