A086767 Last coefficient of the last term in the numerator of the simplified expansion of the solutions of FLT for n=2 for FLT n=1,2,3,..
1, 1, 1, 1, 1, 3, 1, 1, 1, 5, 1, 3, 1, 7, 1, 1, 1, 9, 1, 5, 1, 11, 1, 3, 1, 13, 1, 7, 1, 15, 1, 1, 1, 17, 1, 9, 1, 19, 1, 5, 1, 21, 1, 11, 1, 23, 1, 3, 1, 25, 1, 13, 1, 27, 1, 7, 1, 29, 1, 15, 1, 31, 1, 1, 1, 33, 1, 17, 1, 35, 1, 9, 1, 37, 1, 19, 1, 39, 1, 5, 1, 41, 1, 21, 1, 43, 1, 11, 1, 45, 1, 23
Offset: 0
Examples
b/a 1 (3*a^4 + b^4)/(4*b*a^3) (a^4 + b^4)/(2*b^2*a^2) (5*a^8 + 10*b^4*a^4 + b^8)/(16*b^3*a^5) (3*a^8 + 10*b^4*a^4 + 3*b^8)/(16*b^4*a^4) (7*a^12 + 35*b^4*a^8 + 21*b^8*a^4 + b^12)/(64*b^5*a^7) (a^12 + 7*b^4*a^8 + 7*b^8*a^4 + b^12)/(16*b^6*a^6) (9*a^16 + 84*b^4*a^12 + 126*b^8*a^8 + 36*b^12*a^4 + b^16)/(256*b^7*a^9) (5*a^16 + 60*b^4*a^12 + 126*b^8*a^8 + 60*b^12*a^4 + 5*b^16)/(256*b^8*a^8) ........ (K + cb^m)/2^m1b^m2c^m3 Seq = c for integers K,b,m1,m2,m3,n = 1,2,3...
Links
- Anonymous, Fermat's Theorem for Pythagorean Triples.
Programs
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Maple
sigma := proc(n) local i; add(i,i=convert(n,base,2)) end: a := proc(n) if n=0 or type(n,odd) then 1 else if type(iquo(n,2),odd) then n/2 else n/2^(1-sigma(n)+sigma(n-1)) fi fi end: # Peter Luschny, Aug 03 2009
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PARI
\ verification of general solution in integers \ a>b,x = 2ab,y=a^2-b^2,z=a^2+b^2 \ or FLT n=2 x^n+y^n <> z^n = (2ab)^n + (a^2-b^2)^n <> \(a^2+b^2)^n for n > 2 flt(n,a1,b1) = for(x=0,n,print(f(x,a1,b1))) f(n,a,b) = simplify(((a^2+b^2)^n - (a^2-b^2)^n)/(2*a*b)^n) coeffb(m) = { for(y=1,m, n=y; if(n%2,x=1, while(n%2==0,n=n/2); x=n; ); print1(x",") ) }
Comments