A086833 Minimum number of different addends occurring in any shortest addition chain of Brauer type for a given n, or 0 if n has no shortest addition chain of Brauer type.
1, 1, 1, 2, 2, 2, 2, 3, 2, 3, 3, 3, 3, 3, 3, 4, 4, 3, 3, 4, 3, 4, 5, 4, 4, 4, 3, 4, 4, 4, 4, 5, 5, 5, 4, 4, 4, 4, 4, 5, 5, 4, 6, 5, 4, 6, 4, 5, 5, 5, 5, 5, 5, 4, 4, 5, 4, 5, 5, 5, 5, 5, 4, 6, 6, 6, 6, 6, 6, 5, 5, 5, 5, 5, 5, 5, 7, 5, 5, 6, 4, 6, 7, 5, 6, 7, 5, 6, 6, 5, 5, 7, 5, 5, 5, 6, 6, 6, 6, 6, 6, 6, 6, 6, 5
Offset: 1
Keywords
Examples
a(23)=5 because 23=1+1+2+1+4+9+5 is the shortest addition chain for 23. For n=9 there are A079301(9)=3 different shortest addition chains, all of Brauer type: [1 2 3 6 9] -> 9=1+1+1+3+3 -> 2 different addends {1,3} [1 2 4 5 9] -> 9=1+1+2+1+4 -> 3 different addends {1,2,4} [1 2 4 8 9] -> 9=1+1+2+4+1 -> 3 different addends {1,2,4} The minimum number of different addends is 2, therefore a(9)=2.
Links
- Giovanni Resta, Tables of Shortest Addition Chains, computed by David W. Wilson.
- Index to sequences related to the complexity of n
Crossrefs
Formula
a(n) = 0 if and only if n is in A349044. - Pontus von Brömssen, Apr 25 2025
Extensions
Edited by Hugo Pfoertner, Jun 10 2006
Escape clause added by Pontus von Brömssen, Apr 25 2025
Comments