A092124 a(0) = 2, a(n) = (2^(2^n)+2)*a(n-1) for n>0.
2, 12, 216, 55728, 3652301664, 15686516209310983872, 289365149921256212111714425927549504896, 98465858119637274097902770931519409290135390781788892125023848289699334298368
Offset: 0
Keywords
Examples
a(3)=55728='1101100110110000' -> {{}{{}}{{}{{}}}} -> {{},{{}},{{},{{}}}} -> {0,{0},{0,{0}}} -> {0,1,{0,1}} -> {0,1,2} -> A001477(3)=3.
Links
- Hugo Pfoertner, Table of n, a(n) for n = 0..10
Programs
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Mathematica
RecurrenceTable[{a[0]==2,a[n]==(2^(2^n)+2)a[n-1]},a,{n,8}] (* Harvey P. Dale, Nov 15 2020 *) nxt[{n_,a_}]:={n+1,(2^2^(n+1)+2)a}; NestList[nxt,{0,2},8][[;;,2]] (* Harvey P. Dale, Aug 11 2023 *)
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Python
from functools import lru_cache @lru_cache(maxsize=None) def A092124(n): return ((1<<(1<
A092124(n-1) if n else 2 # Chai Wah Wu, Nov 23 2023
Comments