A092689 Triangle, read by rows, such that the convolution of each row with {1,2} produces a triangle which, after the main diagonal is divided by 2 and the triangle is flattened, equals this flattened form of the original triangle.

1, 1, 1, 3, 1, 3, 7, 5, 3, 7, 19, 13, 13, 7, 19, 51, 39, 33, 33, 19, 51, 141, 111, 99, 85, 89, 51, 141, 393, 321, 283, 259, 229, 243, 141, 393, 1107, 925, 825, 747, 701, 627, 675, 393, 1107, 3139, 2675, 2397, 2195, 2029, 1929, 1743, 1893, 1107, 3139, 8953, 7747

Offset: 0

Author

Paul D. Hanna, Mar 04 2004

Keywords

• nonn
• tabl

Comments

First column and main diagonal forms the central trinomial coefficients (A002426). Row sums form A092690.

Examples

			Rows begin:
{1},
{1,1},
{3,1,3},
{7,5,3,7},
{19,13,13,7,19},
{51,39,33,33,19,51},
{141,111,99,85,89,51,141},
{393,321,283,259,229,243,141,393},
{1107,925,825,747,701,627,675,393,1107},
{3139,2675,2397,2195,2029,1929,1743,1893,1107,3139},
{8953,7747,6989,6419,5987,5601,5379,4893,5353,3139,8953},...
Convolution of each row with {1,2} forms the triangle:
{1,2},
{1,3,2},
{3,7,5,6},
{7,19,13,13,14},
{19,51,39,33,33,38},
{51,141,111,99,85,89,102},
{141,393,321,283,259,229,243,282},...
which, after the main diagonal is divided by 2 and the triangle is flattened, equals the original triangle in flattened form: {1,1,1,3,1,3,7,5,3,7,19,...}.
		

Crossrefs

Cf. A002426, A092683, A092686, A092690.

Programs

PARI

T(n,k)=if(n<0 || k>n,0, if(n==0 && k==0,1, if(n==1 && k<=1,1, if(k==n-1,T(n-1,0), if(k==n,T(n,0), 2*T(n-1,k)+T(n-1,k+1))))))

Formula

T(n, k) = 2*T(n-1, k) + T(n-1, k+1) for 0A002426(n), T(0, 0)=1, T(0, 1)=T(1, 0)=1.