A095250 a(n) = 11111111... (n times) = (10^n-1)/9 reduced mod n.
0, 1, 0, 3, 1, 3, 1, 7, 0, 1, 1, 3, 1, 11, 6, 7, 1, 9, 1, 11, 6, 11, 1, 15, 11, 11, 0, 19, 1, 21, 1, 7, 12, 11, 16, 27, 1, 11, 33, 31, 1, 21, 1, 11, 36, 11, 1, 39, 36, 11, 9, 19, 1, 27, 1, 39, 54, 11, 1, 51, 1, 11, 27, 7, 61, 33, 1, 23, 42, 61, 1, 63, 1, 11, 36, 47, 23, 39, 1, 71, 0, 11, 1, 63
Offset: 1
Keywords
Examples
1111111 mod 7 = 1.
References
- Amarnath Murthy, "On the divisors of Smarandache Unary Sequence", Smarandache Notions Journal, 1-2-3, vol. 11, 2000.
Links
- Harvey P. Dale, Table of n, a(n) for n = 1..1000
Crossrefs
Cf. A002275.
Programs
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Mathematica
Table[Mod[FromDigits[PadRight[{},n,1]],n],{n,90}] (* Harvey P. Dale, Jun 19 2022 *)
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PARI
a(n) = (10^n - 1)/9 % n; \\ Michel Marcus, Jul 03 2019
Formula
a(n) = A002275(n) mod n.
Comments