A095993 Inverse Euler transform of the ordered Bell numbers A000670.
1, 1, 2, 10, 59, 446, 3965, 41098, 484090, 6390488, 93419519, 1498268466, 26159936547, 494036061550, 10035451706821, 218207845446062, 5057251219268460, 124462048466812950, 3241773988588098756, 89093816361187396674, 2576652694087142999421
Offset: 0
Keywords
Links
- Alois P. Heinz, Table of n, a(n) for n = 0..423
Programs
-
Maple
read transforms; A000670 := proc(n) option remember; local k; if n <=1 then 1 else add(binomial(n,k)*A000670(n-k),k=1..n); fi; end; [seq(A000670(i),i=1..30)]; EULERi(%); # The function EulerInvTransform is defined in A358451. a := EulerInvTransform(A000670): seq(a(n), n = 0..22); # Peter Luschny, Nov 21 2022
-
Mathematica
max = 25; b[0] = 1; b[n_] := b[n] = Sum[Binomial[n, k]*b[n-k], {k, 1, n}]; bb = Array[b, max]; s = {}; For[i=1, i <= max, i++, AppendTo[s, i*bb[[i]] - Sum[s[[d]]*bb[[i-d]], {d, i-1}]]]; a[0] = 1; a[n_] := Sum[If[Divisible[ n, d], MoebiusMu[n/d], 0]*s[[d]], {d, 1, n}]/n; Table[a[n], {n, 0, max}] (* Jean-François Alcover, Feb 25 2017 *)
Formula
Product(1/(1-q^n)^(a(n)), n >=1) = sum(A000670(k)*q^k, k>=0).
a(n) ~ n! / (2 * log(2)^(n+1)). - Vaclav Kotesovec, Oct 09 2019
Extensions
a(0)=1 inserted by Alois P. Heinz, Feb 20 2017