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This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A097877 Triangle read by rows: T(n,k) is the number of Dyck n-paths with k large components, 0 <= k <= n/2.

Original entry on oeis.org

1, 1, 1, 1, 1, 4, 1, 12, 1, 1, 34, 7, 1, 98, 32, 1, 1, 294, 124, 10, 1, 919, 448, 61, 1, 1, 2974, 1576, 298, 13, 1, 9891, 5510, 1294, 99, 1, 1, 33604, 19322, 5260, 583, 16, 1, 116103, 68206, 20595, 2960, 146, 1, 1, 406614, 242602, 78954, 13704, 1006, 19, 1, 1440025
Offset: 0

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Author

David Callan, Sep 21 2004

Keywords

Comments

A prime Dyck path is one with exactly one return to ground level. Every nonempty Dyck path decomposes uniquely as a concatenation of prime Dyck paths, called its components. For example, UUDDUD has 2 components: UUDD and UD, of semilength 2 and 1 respectively. A large component is one of semilength >= 2.
Conjecture: This is the statistic "indegree" of elements in Pallo's comb posets. For the statistic "outdegree", see A009766. - F. Chapoton, Apr 18 2023

Examples

			T(3,1) = 4 because each of the 5 Dyck paths of semilength 3 has one large component except for UDUDUD, which has none.
Table begins:
  \ k 0, 1, 2, ...
  n\ ____________________
  0 | 1;
  1 | 1;
  2 | 1,   1;
  3 | 1,   4;
  4 | 1,  12,   1;
  5 | 1,  34,   7;
  6 | 1,  98,  32,  1;
  7 | 1, 294, 124, 10;
  8 | 1, 919, 448, 61, 1;
  ...
		

Crossrefs

The Fine distribution (A065600) counts Dyck paths by number of small components (= number of low peaks).

Formula

G.f.: 2/(1 + t*(1 - 4*z)^(1/2) + (1 - 2*z)(1-t)) = Sum_{n>=0, k>=0} T(n, k) z^n t^k satisfies (1-z)*G = 1 + z*t*(CatalanGF[z]-1)*G. The gf for Dyck paths (A000108) with z marking semilength is CatalanGF[z]:=(1 - sqrt[1 - 4*z])/(2*z). Hence the gf for prime Dyck paths is z*CatalanGF[z] and the gf for non-UD prime Dyck paths is S(z):= z*CatalanGF[z]-z. For fixed k, the gf for (T(n, k))_{n>=0} is S(z)^k/(1-z)^(k+1). This is clear because 1/(1-z) is the gf for all-UD Dyck paths (including the empty one) and a Dyck path with k large components is a product (uniquely) of an all-UD, a non-UD prime, an all-UD, a non-UD prime, ... with k non-UD primes and k+1 all-UDs.