cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-3 of 3 results.

A103315 Number of minimum dominating sets for the n X n knight graph.

Original entry on oeis.org

1, 1, 8, 9, 47, 127, 10, 2, 2, 4, 800, 2, 152, 4, 504, 2, 212, 19562
Offset: 1

Views

Author

N. J. A. Sloane, Mar 20 2005, following a suggestion from Lee Morgenstern

Keywords

Comments

In other words, as made explicit in the old name: Sequence A006075 gives minimum number of knights needed to cover an n X n board (i.e., the domination number of the n X n knight graph). This sequence (A103315) gives total number of solutions using A006075(n) knights (compare A006076).

Crossrefs

Cf. A006075 (domination number of the n X n knight graph).
Cf. A006076 (inequivalent number of minimum dominating sets).
Cf. A098604.

Extensions

New name from Eric W. Weisstein, Sep 06 2021

A006076 Sequence A006075 gives minimal number of knights needed to cover an n X n board. This sequence gives number of inequivalent solutions using A006075(n) knights.

Original entry on oeis.org

1, 1, 2, 3, 8, 23, 3, 1, 1, 2, 100, 1, 20, 1, 63, 1, 29, 2551
Offset: 1

Views

Author

Keywords

References

  • David C. Fisher, On the N X N Knight Cover Problem, Ars Combinatoria 69 (2003), 255-274.
  • M. Gardner, Mathematical Magic Show. Random House, NY, 1978, p. 194.
  • Bernard Lemaire, Knights Covers on N X N Chessboards, J. Recreational Mathematics, Vol. 31-2, 2003, 87-99.
  • Frank Rubin, Improved knight coverings, Ars Combinatoria 69 (2003), 185-196.
  • N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).

Crossrefs

Cf. A006075 (number of solutions), A098604 (rectangular board). A103315 gives the total number of solutions.

Extensions

a(11) was found in 1973 by Bernard Lemaire. (Philippe Deléham, Jan 06 2004)
a(13)-a(17) from the Morgenstern web site, Nov 08 2004
a(18) from the Morgenstern web site, Mar 20 2005

A110217 Cone C(n,m,k) read by planes and rows, for 1 <= k <= m <= n: minimal number of knights needed to cover a k X m X n board.

Original entry on oeis.org

1, 2, 4, 8, 3, 4, 8, 4, 6, 6, 4, 4, 8, 4, 6, 6, 4, 6, 7, 8, 5, 4, 8, 4, 6, 6, 4, 6, 7, 8, 5, 6, 8, 10, 13, 6, 4, 6, 4, 7, 6, 4, 8, 8, 12, 6, 8, 10, 12
Offset: 1

Views

Author

Nikolaus Meyberg (Nikolaus.Meyberg(AT)t-online.de), Jul 17 2005

Keywords

Examples

			Cone starts:
1..2....3......4........5............6.................
...4.8..4.8....4.8......4.8..........4..6
........4.6.6..4.6.6....4.6.6........4..7..6
...............4.6.7.8..4.6.7..8.....4..8..8.12
........................5.6.8.10.13..6..8.10.12.?
.....................................8.11.12..?....
		

Crossrefs

C(n, n, 1) = A006075(n), C(n, k, 1) = A098604(n, k), C(n, n, n) = A110214(n). A110218 gives number of inequivalent ways to cover the board using C(n, m, k) knights, A110219 gives total number.

Formula

How many knights with move vector (2, 1, 0) are needed to occupy or attack every field of a k X m X n board? Knights may attack each other.
Showing 1-3 of 3 results.