A106422 Smallest number beginning with 2 and having exactly n prime divisors counted with multiplicity.
2, 21, 20, 24, 200, 216, 288, 256, 2592, 2304, 2048, 20736, 20480, 24576, 204800, 221184, 294912, 262144, 2654208, 2359296, 2097152, 21233664, 20971520, 25165824, 209715200, 226492416, 201326592, 268435456, 2013265920, 2415919104
Offset: 1
Examples
a(1) = 2, a(5) = 200 = 2^3*5^2.
Links
- Robert Israel, Table of n, a(n) for n = 1..3303
Programs
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Maple
f:= proc(n) uses priqueue; local pq, t, p, x, i; initialize(pq); insert([-2^n, 2$n], pq); do t:= extract(pq); x:= -t[1]; if floor(x/10^ilog10(x)) = 2 then return x fi; p:= nextprime(t[-1]); for i from n+1 to 2 by -1 while t[i] = t[-1] do insert([t[1]*(p/t[-1])^(n+2-i), op(t[2..i-1]), p$(n+2-i)], pq) od; od end proc: map(f, [$1..40]); # Robert Israel, Apr 15 2025
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Python
from itertools import count from math import isqrt, prod from sympy import primerange, integer_nthroot, primepi def A106422(n): if n == 1: return 2 def g(x,a,b,c,m): yield from (((d,) for d in enumerate(primerange(b,isqrt(x//c)+1),a)) if m==2 else (((a2,b2),)+d for a2,b2 in enumerate(primerange(b,integer_nthroot(x//c,m)[0]+1),a) for d in g(x,a2,b2,c*b2,m-1))) def f(x): return int(sum(primepi(x//prod(c[1] for c in a))-a[-1][0] for a in g(x,0,1,1,n))) for l in count(len(str(1<
mmin: while kmax-kmin > 1: kmid = kmax+kmin>>1 mmid = f(kmid) if mmid > mmin: kmax, mmax = kmid, mmid else: kmin, mmin = kmid, mmid return kmax # Chai Wah Wu, Sep 12 2024