cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-4 of 4 results.

A109234 a(n) = floor(n*sinh(1)).

Original entry on oeis.org

1, 2, 3, 4, 5, 7, 8, 9, 10, 11, 12, 14, 15, 16, 17, 18, 19, 21, 22, 23, 24, 25, 27, 28, 29, 30, 31, 32, 34, 35, 36, 37, 38, 39, 41, 42, 43, 44, 45, 47, 48, 49, 50, 51, 52, 54, 55, 56, 57, 58, 59, 61, 62, 63, 64, 65, 66, 68, 69, 70, 71, 72, 74, 75, 76, 77
Offset: 1

Views

Author

Reinhard Zumkeller, Jun 23 2005

Keywords

Comments

Beatty sequence for sinh(1) = (e-1/e)/2 = 1.17520... = A073742; complement of A109235.

Crossrefs

A109237 a(n) = floor(n*coth(1)).

Original entry on oeis.org

1, 2, 3, 5, 6, 7, 9, 10, 11, 13, 14, 15, 17, 18, 19, 21, 22, 23, 24, 26, 27, 28, 30, 31, 32, 34, 35, 36, 38, 39, 40, 42, 43, 44, 45, 47, 48, 49, 51, 52, 53, 55, 56, 57, 59, 60, 61, 63, 64, 65, 66, 68, 69, 70, 72, 73, 74, 76, 77, 78, 80, 81, 82, 84, 85, 86
Offset: 1

Views

Author

Reinhard Zumkeller, Jun 23 2005

Keywords

Comments

Beatty sequence for coth(1) = (e^2+1)/(e^2-1) = 1.31303... = A073747; complement of A109238.
From Reinhard Zumkeller, Aug 11 2009: (Start)
a(n) = A164087(n) for n <= 20;
a(n) = A109239(A109238(n)) and A109239(a(n)) = A109238(n). (End)

Crossrefs

Extensions

Typo in comment corrected by Reinhard Zumkeller, Aug 10 2009

A109233 Self-inverse integer permutation induced by Beatty sequences for (e+1/e)/2 and (e^2+1)/(e-1)^2.

Original entry on oeis.org

2, 1, 5, 8, 3, 11, 14, 4, 17, 19, 6, 22, 25, 7, 28, 31, 9, 34, 10, 36, 39, 12, 42, 45, 13, 48, 51, 15, 53, 56, 16, 59, 62, 18, 65, 20, 68, 71, 21, 73, 76, 23, 79, 82, 24, 85, 88, 26, 90, 93, 27, 96, 29, 99, 102, 30, 105, 107, 32, 110, 113, 33, 116, 119
Offset: 1

Views

Author

Reinhard Zumkeller, Jun 23 2005

Keywords

Crossrefs

Formula

a(A109231(n))=A109232(n) and a(A109232(n))=A109231(n).

A109232 a(n) = floor(n*(e^2+1)/(e-1)^2).

Original entry on oeis.org

2, 5, 8, 11, 14, 17, 19, 22, 25, 28, 31, 34, 36, 39, 42, 45, 48, 51, 53, 56, 59, 62, 65, 68, 71, 73, 76, 79, 82, 85, 88, 90, 93, 96, 99, 102, 105, 107, 110, 113, 116, 119, 122, 125, 127, 130, 133, 136, 139, 142, 144, 147, 150, 153, 156, 159, 161
Offset: 1

Views

Author

Reinhard Zumkeller, Jun 23 2005

Keywords

Comments

Beatty sequence for (e^2+1)/(e-1)^2 = 2.84134...; complement of A109231.
The constant is 2.841347188415584637890827045432999205763311253301102304707920819444...
Similar to but different from A140099. - N. J. A. Sloane, Sep 01 2016

Crossrefs

Programs

  • Mathematica
    Table[Floor[(n(E^2+1))/(E-1)^2],{n,60}] (* Harvey P. Dale, Dec 21 2022 *)
Showing 1-4 of 4 results.