cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A109451 a(1)=1; a(n) = smallest positive integer not already present such that a(n-1) and a(n) have a different number of 1's in their binary expansions.

Original entry on oeis.org

1, 3, 2, 5, 4, 6, 7, 8, 9, 11, 10, 13, 12, 14, 15, 16, 17, 19, 18, 21, 20, 22, 23, 24, 25, 27, 26, 29, 28, 30, 31, 32, 33, 35, 34, 37, 36, 38, 39, 40, 41, 43, 42, 45, 44, 46, 47, 48, 49, 51, 50, 53, 52, 54, 55, 56, 57, 59, 58, 61, 60, 62, 63, 64, 65, 67, 66, 69, 68, 70, 71, 72
Offset: 1

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Author

Leroy Quet, Aug 27 2005

Keywords

Comments

This sequence is a permutation of the positive integers.

Examples

			Among the positive integers (10, 11,12, 13,...) not among the first 9 terms of the sequence, 10 (decimal) has 2 1's in its binary form (1010), the same number of 1's as 9 in binary (1001). 11 (decimal), however, has 3 ones in its binary form (1011), so a(10) = 11.
		

Crossrefs

Cf. A000120.

Programs

  • Maple
    Cands:= [$2..100]:
    Ones:= map(t -> convert(convert(t,base,2),`+`), Cands):
    A[1]:= 1: dc:= 1:
    for n from 2 do
       found:= false;
       for k from 1 to nops(Cands) while not found do
         if Ones[k] <> dc then
            found:= true;
            A[n]:= Cands[k];
            dc:= Ones[k];
            Cands:= subsop(k=NULL,Cands);
            Ones:= subsop(k=NULL,Ones);
         fi
       od;
       if not found then break fi;
    od:
    seq(A[i],i=1..n-1); # Robert Israel, May 03 2016
  • Mathematica
    a = {1}; Nest[AppendTo[a, SelectFirst[Range@ 120, And[! MemberQ[a, #], First@ DigitCount[#, 2] != First@ DigitCount[Last@ a, 2]] &]] &, a, 71] (* Michael De Vlieger, May 03 2016, Version 10 *)

Formula

a(n) = n+1 if n == 2 or 4 (mod 8), n-1 if n == 3 or 5 (mod 8), n otherwise. - Peter Kagey, May 03 2016
G.f.: x*(1 + 2*x - 2*x^2 + x^3 + x^4 + x^5)/((1 - x)^2*(1 + x + x^4 + x^5)). - Ilya Gutkovskiy, May 04 2016

Extensions

Extended by Ray Chandler, Aug 27 2005