cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-4 of 4 results.

A114439 Indices of semiprime pentagonal numbers.

Original entry on oeis.org

4, 5, 6, 10, 13, 14, 29, 34, 38, 41, 46, 53, 58, 73, 86, 94, 101, 106, 109, 118, 134, 149, 181, 206, 214, 218, 226, 233, 254, 274, 281, 293, 314, 326, 349, 394, 398, 401, 409, 421, 449, 454, 458, 461, 478, 538, 541, 566, 569, 613, 626, 634, 661, 673, 694
Offset: 1

Views

Author

Jonathan Vos Post, Feb 14 2006

Keywords

Comments

P(2) = 5 is the only prime pentagonal number, all other factor as P(k) = (k/2)*(3*k-1) or k*((3*k-1)/2) and thus have at least 2 prime factors. P(k) is semiprime iff [k prime and (3*k-1)/2 prime] or [k/2 prime and 3*k-1 prime]. A115709 is pentagonal numbers (A000326) whose digit reversal is a semiprime (A001358).

Examples

			a(1) = 4 because P(4) = PentagonalNumber(4) = 4*(3*4 -1)/2 = 22 = 2 * 11 is semiprime.
a(2) = 5 because P(5) = 5*(3*5 -1)/2 = 35 = 5 * 7 is semiprime.
a(7) = 29 because P(29) = 29*(3*29 -1)/2 = 1247 = 29 * 43 is semiprime.
a(8) = 34 because P(34) = 34*(3*34 -1)/2 = 1717 = 17 * 101 is semiprime.
a(17) = 101 because P(101) = 101*(3*101 -1)/2 = 15251 = 101 * 151 is semiprime.
		

Crossrefs

Programs

Formula

{a(n)} = {k such that A001222(A000326(k)) = 2}.
{a(n)} = {k such that k*(3*k-1)/2 has exactly 2 prime factors}.
{a(n)} = {k such that A000326(k) is an element of A001358}.

Extensions

More terms from Giovanni Resta, Jun 14 2016

A115708 Semiprimes (A001358) whose digit reversal is a pentagonal number (A000326).

Original entry on oeis.org

10, 15, 21, 22, 235, 287, 517, 529, 671, 1513, 1555, 2611, 5137, 5331, 6241, 7017, 7171, 7421, 7597, 7814, 10078, 10913, 15011, 15094, 15214, 15251, 20395, 20603, 21542, 23129, 24501, 24873, 25157, 26851, 27161, 51998, 53297, 54989, 55551
Offset: 1

Views

Author

Giovanni Resta, Jan 31 2006

Keywords

Examples

			235=5*47 is semiprime and 532 is the 19th pentagonal number.
		

Crossrefs

Programs

  • Mathematica
    Select[Range[60000],PrimeOmega[#]==2&&IntegerQ[(1+Sqrt[1+24* IntegerReverse[#]])/ 6]&] (* Harvey P. Dale, Apr 27 2022 *)

A114441 Indices of 3-almost prime pentagonal numbers.

Original entry on oeis.org

3, 7, 8, 9, 17, 18, 20, 21, 22, 23, 25, 26, 28, 30, 31, 37, 44, 49, 50, 61, 62, 65, 66, 69, 71, 74, 76, 78, 79, 85, 89, 93, 97, 98, 113, 116, 121, 122, 129, 130, 133, 137, 141, 146, 148, 151, 154, 157, 158, 161, 164, 166, 170, 173, 174, 178, 185, 186, 188, 190, 193, 194
Offset: 1

Views

Author

Jonathan Vos Post, Feb 14 2006

Keywords

Comments

P(2) = 5 is the only prime pentagonal number, all other factor as P(k) = (k/2)*(3*k-1) or k*((3*k-1)/2) and thus have at least 2 prime factors. P(k) is semiprime iff [k prime and (3*k-1)/2 prime] or [k/2 prime and 3*k-1 prime].

Examples

			a(1) = 3 because P(3) = PentagonalNumber(3) = 3*(3*3 -1)/2 = 12 = 2^2 * 3 is a 3-almost prime.
a(2) = 7 because P(7) = 7*(3*7 -1)/2 = 70 = 2 * 5 * 7 is a 3-almost prime.
		

Crossrefs

Programs

  • Maple
    A000326 := proc(n) n*(3*n-1)/2 ; end: isA014612 := proc(n) option remember ; RETURN( numtheory[bigomega](n) = 3) ; end: for n from 1 to 400 do if isA014612(A000326(n)) then printf("%d,",n) ; fi; od: # R. J. Mathar, Jan 27 2009
  • Mathematica
    Select[Range[200], PrimeOmega[PolygonalNumber[5, #]] == 3 &] (* Amiram Eldar, Oct 06 2024 *)

Formula

{a(n)} = {k such that A001222(A000326(k)) = 3}.
{a(n)} = {k such that k*(3*k-1)/2 has exactly 3 prime factors}.
{a(n)} = {k such that A000326(k) is an element of A014612}.

Extensions

125 removed, 145 replaced with 146 by R. J. Mathar, Jan 27 2009

A114443 Indices of 4-almost prime pentagonal numbers.

Original entry on oeis.org

12, 15, 16, 19, 24, 33, 36, 39, 45, 47, 52, 55, 56, 57, 60, 68, 70, 77, 82, 83, 84, 88, 90, 95, 102, 103, 104, 105, 110, 111, 114, 119, 124, 127, 138, 140, 142, 143, 145, 150, 153, 156, 163, 169, 172, 177, 179, 182, 183, 191, 196, 198
Offset: 1

Views

Author

Jonathan Vos Post, Feb 14 2006

Keywords

Comments

P(2) = 5 is the only prime pentagonal number, all other factor as P(k) = (k/2)*(3*k-1) or k*((3*k-1)/2) and thus have at least 2 prime factors. P(k) is semiprime iff [k prime and (3*k-1)/2 prime] or [k/2 prime and 3*k-1 prime].

Examples

			a(1) = 12 because P(12) = A000326(12) = 12*(3*12-1)/2 = 210 = 2 * 3 * 5 * 7 is a 4-almost prime (in fact the primorial prime(4)#).
a(3) = 16 because P(16) = 16*(3*16-1)/2 = 376 = 2^3 * 47 is a 4-almost prime (the prime factors need not be distinct).
		

Crossrefs

Programs

  • Mathematica
    Select[Range[400], PrimeOmega[PolygonalNumber[5, #]] == 4 &] (* Amiram Eldar, Oct 06 2024 *)

Formula

{a(n)} = {k such that A001222(A000326(k)) = 4}.
{a(n)} = {k such that k*(3*k-1)/2 has exactly 4 prime factors}.
{a(n)} = {k such that A000326(k) is an element of A014613}.

Extensions

82 inserted by R. J. Mathar, Dec 22 2010
Showing 1-4 of 4 results.