A116613 Values of n such that prime(2n+1) mod 12 = 5.

1, 3, 6, 16, 17, 22, 25, 27, 28, 35, 38, 39, 43, 44, 48, 56, 59, 61, 67, 68, 69, 82, 99, 100, 104, 111, 113, 122, 127, 129, 132, 133, 145, 146, 156, 161, 162, 171, 172, 176, 179, 183, 186, 189, 190, 202, 209, 210, 234, 238, 250, 251, 258, 261, 272, 275, 280, 284

Offset: 1

Author

Roger L. Bagula, Mar 29 2006

Keywords

• nonn

Examples

			25 is in the sequence because the 51st prime is 233 and 233 mod 12 = 5.
		

Links

• G. C. Greubel, Table of n, a(n) for n = 1..1000

Crossrefs

Cf. A116602, A116610, A116612-A116617, A160591-A160594. - M. F. Hasler, May 22 2009

Programs

Maple

a:=proc(n) if ithprime(2*n+1) mod 12 = 5 then n else fi end: seq(a(n),n=0..300);

Mathematica

Select[Range[0, 500], Mod[Prime[2*# + 1], 12] == 5 &] (* G. C. Greubel, Nov 19 2017 *)

PARI

for(n=1,999, prime(2*n+1)%12==5 & print1(n",")) \\ M. F. Hasler, May 22 2009

Formula

Equals the integer part of { odd terms in A160591 = A000720(A040117) } / 2. - M. F. Hasler, May 22 2009

Extensions

Edited by N. J. A. Sloane, Apr 05 2006