A118166 Smallest term in the Hofstadter sequence A005243 having exactly n representations as sum of consecutive earlier terms.
1, 3, 11, 43, 35, 162, 311, 1203, 2405, 2769, 4257, 5772, 9639, 18711, 13860, 40635, 39270, 61425, 45045, 75075, 107415, 53865, 159075, 239085, 197505, 225225, 137445, 621621, 373065, 634095, 812175, 412335, 1036035, 1119195, 883575, 1673595
Offset: 0
Keywords
Examples
a(8) = A005243(A118165(8)) = A005243(2210) = 2405: #1: 1203 + 1202 = Sum(A005243[1049:1050]) = 2405, #2: 803 + 802 + 800 = Sum(A005243[671:673]) = 2405, #3: 483 + 482 + 481 + 480 + 479 = Sum(A005243[382:386]), #4: 306 + 304 + 302 + 301 + 300 + 299 + 297 + 296 = Sum(A005243[224:231]) = 2405, #5: 224 + 223 + 222 + 221 + 220 + 219 + 218 + 216 + 215 + 214 + 213 = Sum(A005243[153:163]) = 2405, #6: 145 + 143 + 142 + 141 + 140 + 139 + 138 + 137 + 135 + 134 + 132 + 130 + 129 + 127 + 126 + 124 + 122 + 121 = Sum(A005243[82:99]) = 2405, #7: 129 + 127 + 126 + 124 + 122 + 121 + 119 + 118 + 117 + 116 + 115 + 113 + 112 + 111 + 110 + 108 + 106 + 105 + 104 + 102 + 100 = Sum(A005243[67:87]) = 2405, #8: 95 + 94 + 93 + 92 + 91 + 90 + 88 + 87 + 86 + 84 + 82 + 81 + 80 + 78 + 77 + 76 + 75 + 73 + 72 + 71 + 70 + 69 + 68 + 67 + 65 + 62 + 60 + 59 + 58 + 57 + 54 + 51 = Sum(A005243[32:63]) = 2405.
Links
- Eric Weisstein's World of Mathematics, Hofstadter Sequences
Crossrefs
Cf. A118164.
Extensions
a(15)-a(35) from Donovan Johnson, Feb 16 2011
Comments