A118720 Cubes which are divisible by the sum of their digits.
1, 8, 27, 216, 512, 1000, 1728, 4913, 5832, 8000, 13824, 17576, 19683, 27000, 35937, 46656, 59319, 64000, 74088, 110592, 125000, 157464, 185193, 216000, 287496, 314432, 328509, 343000, 373248, 421875, 474552, 512000, 592704, 658503, 729000
Offset: 1
Examples
4913 is in the sequence because it is a cube, the sum of its digits is 4+9+1+3=17 and 4913 is divisible by 17.
Links
- Robert Israel, Table of n, a(n) for n = 1..10000
Programs
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Maple
select(t -> t mod convert(convert(t,base,10),`+`) = 0, map(t -> t^3, [$1..100])); # Robert Israel, Jun 28 2017
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Mathematica
Select[Range[100]^3,Divisible[#,Total[IntegerDigits[#]]]&] (* Harvey P. Dale, Apr 25 2011 *)
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PARI
isok(n) = ispower(n,3) && ((n % sumdigits(n)) == 0); \\ Michel Marcus, Jun 28 2017
Comments