A120001 Where record values of A119999 occur.

0, 10, 12, 21, 102, 112, 123, 213, 312, 412, 512, 612, 712, 812, 912, 1012, 1023, 1123, 1213, 1234, 1324, 1423, 2113, 2134, 3124, 4123, 5123, 6123, 7123, 8123, 9123, 10123, 10234, 11213, 11234, 12134, 12345, 13245, 14235, 15234, 16234, 17234, 18234, 19234, 21134, 21345

Offset: 1

Author

Reinhard Zumkeller, Jun 13 2006

Keywords

• nonn
• base

Comments

A120000(n)=A119999(a(n)) and A119999(m) < A120000(n) for m

problem: smallest m>1023456789 such that A119999(m)>A119999(1023456789)?

From David A. Corneth, Sep 07 2022: (Start)

Does every term >= 10 contain the digit 1?

Does every term >= 12 contain the digits 1 and 2?

Does every term >= 1023 contain the digits 1, 2 and 3?

Does every term >= 11234 contain the digits 1, 2, 3 and 4?

Does every term >= 112345 contain the digits 1, 2, 3, 4 and 5? (End)

Examples

			21 is in the sequence as A119999(21) = 12 and 12 is the largest value of A119999(k) for k in [0, 21]. - _David A. Corneth_, Sep 07 2022
		

Links

• David A. Corneth, Table of n, a(n) for n = 1..51

Crossrefs

Cf. A001399, A001400, A004526, A119999, A120000.

Extensions

More terms from David A. Corneth, Sep 07 2022

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