cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-4 of 4 results.

A120982 Triangle read by rows: T(n,k) is the number of ternary trees with n edges and having k vertices of outdegree 2 (n >= 0, k >= 0).

Original entry on oeis.org

1, 3, 9, 3, 28, 27, 93, 162, 18, 333, 825, 270, 1272, 3915, 2430, 135, 5085, 18144, 17199, 2835, 20925, 84000, 106596, 34020, 1134, 87735, 391554, 612360, 308448, 30618, 372879, 1838295, 3369600, 2364390, 459270, 10206, 1602450, 8674380
Offset: 0

Views

Author

Emeric Deutsch, Jul 21 2006

Keywords

Comments

A ternary tree is a rooted tree in which each vertex has at most three children and each child of a vertex is designated as its left or middle or right child.

Examples

			T(2,1)=3 because we have (Q,L,M), (Q,L,R) and (Q,M,R), where Q denotes the root and L (M,R) denotes a left (middle, right) child of Q.
Triangle starts:
    1;
    3;
    9,   3;
   28,  27;
   93, 162,  18;
  333, 825, 270;
		

Crossrefs

Programs

  • Maple
    T:=(n,k)->(1/(n+1))*binomial(n+1,k)*sum(3^(n-k-3*q)*binomial(n+1-k,k+1+2*q)*binomial(n-2*k-2*q,q),q=0..n/2-k):for n from 0 to 12 do seq(T(n,k),k=0..floor(n/2)) od; # yields sequence in triangular form

Formula

T(n,k) = (1/(n+1))*binomial(n+1,k)*Sum_{j=0..floor(n/2)-k} 3^(n-k-3j)*binomial(n+1-k, k+1+2j)*binomial(n-2k-2j, j).
G.f.: G = G(t,z) satisfies G = 1 + 3zG + 3tz^2*G^2 + z^3*G^3.
Row n has 1+floor(n/2) terms.
Row sums yield A001764.
T(n,0) = A120985(n).
Sum_{k>=1} k*T(n,k) = 3*binomial(3n,n-2) = 3*A003408(n-2).

A120429 Triangle read by rows: T(n,k) is the number of ternary trees with n edges and having k leaves (i.e., vertices of degree 0; n>=0, k>=1). A ternary tree is a rooted tree in which each vertex has at most three children and each child of a vertex is designated as its left or middle or right child.

Original entry on oeis.org

1, 3, 9, 3, 27, 27, 1, 81, 162, 30, 243, 810, 360, 15, 729, 3645, 2970, 405, 3, 2187, 15309, 19845, 5670, 252, 6561, 61236, 115668, 56700, 6426, 84, 19683, 236196, 612360, 459270, 98658, 4536, 12, 59049, 885735, 3018060, 3214890, 1122660
Offset: 0

Views

Author

Emeric Deutsch, Jul 21 2006

Keywords

Comments

Row n has n + 1 - ceiling(n/3) terms.
Row sums yield A001764.
T(n,1) = 3^n = A000244(n).
Sum_{k>=1} k*T(n,k) = binomial(3n,n) = A005809(n).

Examples

			T(2,2)=3 because we have (Q,L,M), (Q,L,R) and (Q,M,R), where Q denotes the root and L (M,R) denotes a left (middle, right) child of Q.
Triangle starts:
    1;
    3;
    9,   3;
   27,  27,   1;
   81, 162,  30;
  243, 810, 360,  15;
		

Crossrefs

Programs

  • Maple
    T:=proc(n,k) if k<=n+1-ceil(n/3) then (1/(n+1))*binomial(n+1,k)*sum(3^(n+j-2*k+2)*binomial(n+1-k,j)*binomial(j,k-1-j),j=0..n+1-k) else 0 fi end: 1; for n from 1 to 11 do seq(T(n,k),k=1..n+1-ceil(n/3)) od; # yields sequence in triangular form

Formula

T(n,k) = (1/(n+1))*binomial(n+1,k)*Sum_{j=0..n+1-k}3^(n-2k+j+2)*binomial(n+1-k,j)*binomial(j,k-1-j).
G.f. = G = G(t,z) satisfies G = (1+z(G-1+t))^3.

A120983 Triangle read by rows: T(n,k) is the number of ternary trees with n edges and having k vertices of outdegree 3 (n >= 0, k >= 0).

Original entry on oeis.org

1, 3, 12, 54, 1, 261, 12, 1323, 105, 6939, 810, 3, 37341, 5859, 63, 205011, 40824, 840, 1143801, 277830, 9072, 12, 6466230, 1861380, 86670, 360, 36960300, 12335895, 764478, 6435, 213243435, 81120204, 6377778, 89100, 55, 1240219269, 530408736
Offset: 0

Views

Author

Emeric Deutsch, Jul 21 2006

Keywords

Comments

A ternary tree is a rooted tree in which each vertex has at most three children and each child of a vertex is designated as its left or middle or right child.

Examples

			T(3,1)=1 because we have (Q,L,M,R), where Q denotes the root and L (M,R) denotes a left (middle, right) child of Q.
Triangle starts:
     1;
     3;
    12;
    54,   1;
   261,  12;
  1323, 105;
  6939, 810, 3;
		

Crossrefs

Programs

  • Maple
    T:=(n,k)->(1/(n+1))*binomial(n+1,k)*sum(3^j*binomial(n+1-k,j)*binomial(j,n-3*k-j),j=0..n+1-k): for n from 0 to 14 do seq(T(n,k),k=0..floor(n/3)) od; # yields sequence in triangular form

Formula

T(n,k) = (1/(n+1))*binomial(n+1,k)*Sum_{j=0..n+1-k} 3^j*binomial(n+1-k, j)*binomial(j, n-3k-j).
G.f.: G = G(t,z) satisfies G = 1 + 3zG + 3z^2*G^2 + tz^3*G^3.
Row n has 1+floor(n/3) terms.
Row sums yield A001764.
T(n,0) = A107264(n).
Sum_{k>=1} k*T(n,k) = binomial(3n, n-3) = A004321(n).

A120984 Number of ternary trees with n edges and having no vertices of degree 1. A ternary tree is a rooted tree in which each vertex has at most three children and each child of a vertex is designated as its left or middle or right child.

Original entry on oeis.org

1, 0, 3, 1, 18, 15, 138, 189, 1218, 2280, 11826, 27225, 123013, 325611, 1346631, 3919188, 15318342, 47563620, 179405250, 582336054, 2148831144, 7191954822, 26193070008, 89559039141, 323765075223, 1123859351610, 4047466156545
Offset: 0

Views

Author

Emeric Deutsch, Jul 21 2006

Keywords

Comments

Column 0 of A120981.

Examples

			a(2)=3 because we have (Q,L,M), (Q,L,R) and (Q,M,R), where Q denotes the root and L (M,R) denotes a left (middle, right) child of Q.
		

Crossrefs

Programs

  • Maple
    a:=n->sum(3^(3*j-n)*binomial(n+1,j)*binomial(j,n-2*j),j=0..n+1)/(n+1): seq(a(n),n=0..30);
  • Mathematica
    Array[Sum[3^(3 j - #)*Binomial[# + 1, j]*Binomial[j, # - 2 j], {j, 0, # + 1}]/(# + 1) &, 27, 0] (* Michael De Vlieger, Jul 02 2021 *)

Formula

a(n) = (1/(n+1))*Sum_{j=0..n+1} 3^(3*j-n)*binomial(n+1,j)*binomial(j,n-2*j).
G.f.: G(z) satisfies G=1+3z^2*G^2+z^3*G^3.
D-finite with recurrence 2*(2*n+3)*(n+1)*a(n) +3*(3*n+2)*(n-1)*a(n-1) -18*(3*n+1)*(n-1)*a(n-2) -135*(n-1)*(n-2)*a(n-3)=0. - R. J. Mathar, Jul 26 2022
a(n) = (1/(n+1)) * Sum_{k=0..n} (-3)^k * binomial(n+1,k) * binomial(3*n-3*k+3,n-k). - Seiichi Manyama, Mar 23 2024
Showing 1-4 of 4 results.