A121335 Triangle, read by rows, where T(n,k) = C( n*(n+1)/2 + n-k + 1, n-k), for n>=k>=0.
1, 3, 1, 15, 5, 1, 120, 36, 8, 1, 1365, 364, 78, 12, 1, 20349, 4845, 969, 153, 17, 1, 376740, 80730, 14950, 2300, 276, 23, 1, 8347680, 1623160, 278256, 40920, 4960, 465, 30, 1, 215553195, 38320568, 6096454, 850668, 101270, 9880, 741, 38, 1, 6358402050
Offset: 0
Examples
Triangle begins: 1; 3, 1; 15, 5, 1; 120, 36, 8, 1; 1365, 364, 78, 12, 1; 20349, 4845, 969, 153, 17, 1; 376740, 80730, 14950, 2300, 276, 23, 1; 8347680, 1623160, 278256, 40920, 4960, 465, 30, 1; 215553195, 38320568, 6096454, 850668, 101270, 9880, 741, 38, 1; ...
Crossrefs
Programs
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PARI
T(n,k)=binomial(n*(n+1)/2+n-k+1,n-k)
Formula
Remarkably, row n of the matrix inverse (A121440) equals row n of A121412^(-n*(n+1)/2-2). Further, the following matrix products of triangles of binomial coefficients are equal: A121412 = A121334*A122178^-1 = A121335*A121334^-1 = A121336*A121335^-1, where row n of H=A121412 equals row (n-1) of H^(n+1) with an appended '1'.
Comments