cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A124508 a(n) = 2^BigO(n) * 3^omega(n), where BigO = A001222 and omega = A001221, the numbers of prime factors of n with and without repetitions.

Original entry on oeis.org

1, 6, 6, 12, 6, 36, 6, 24, 12, 36, 6, 72, 6, 36, 36, 48, 6, 72, 6, 72, 36, 36, 6, 144, 12, 36, 24, 72, 6, 216, 6, 96, 36, 36, 36, 144, 6, 36, 36, 144, 6, 216, 6, 72, 72, 36, 6, 288, 12, 72, 36, 72, 6, 144, 36, 144, 36, 36, 6, 432, 6, 36, 72, 192, 36, 216, 6, 72, 36, 216, 6, 288, 6
Offset: 1

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Author

Reinhard Zumkeller, Nov 04 2006

Keywords

Crossrefs

Programs

  • Mathematica
    Table[2^PrimeOmega[n] 3^PrimeNu[n],{n,80}] (* Harvey P. Dale, Mar 26 2013 *)
  • PARI
    a(n) = my(f = factor(n)); 2^bigomega(f) * 3^omega(f); \\ Amiram Eldar, Jul 11 2023

Formula

Multiplicative with p^e -> 3*2^e, p prime and e>0.
a(n) = A061142(n)*A074816(n) = A000079(A001222(n))*A000244(A001221(n)).
A124509 gives the range: A124509(n) = a(A124510(n)) and a(m) <> a(A124510(n)) for m < A124510(n).
For primes p, q with p <> q: a(p) = 6; a(p*q) = 36; a(p^k) = 3*2^k, k>0.
For squarefree numbers m: a(m) = 6^omega(m).
A001222(a(n)) = A001222(n)+1; A001221(a(n)) = 2 for n > 1.
A124511(n) = a(a(n)); A124512(n) = a(a(a(n))).

A124509 Range of A124508.

Original entry on oeis.org

1, 6, 12, 24, 36, 48, 72, 96, 144, 192, 216, 288, 384, 432, 576, 768, 864, 1152, 1296, 1536, 1728, 2304, 2592, 3072, 3456, 4608, 5184, 6144, 6912, 7776, 9216, 10368, 12288, 13824, 15552, 18432, 20736, 24576, 27648, 31104, 36864, 41472, 46656, 49152, 55296, 62208
Offset: 1

Views

Author

Reinhard Zumkeller, Nov 04 2006

Keywords

Comments

1 together with numbers of the form 2^i * 3^j with i >= j >= 1. - Amiram Eldar, Jul 11 2023

Crossrefs

Subsequence of A003586.
A007283 is a subsequence.

Programs

  • Mathematica
    With[{max = 70000}, Join[{1}, Sort[Flatten[Table[2^i*3^j, {i, 1, Log2[max]}, {j, 1, Min[i, Log[3, max/2^i]]}]]]]] (* Amiram Eldar, Jul 11 2023 *)

Formula

a(n) = A124508(A124510(n)).
Sum_{n>=1} 1/a(n) = 7/5. - Amiram Eldar, Jul 11 2023

Extensions

Missing term a(43) inserted and more terms added by Amiram Eldar, Jul 11 2023
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